英文:
How do i use Loop for my Chinese Zodiac Sign Java Project
问题
我开始学习Java，我是一个完全的新手。我决定在我的项目中制作生肖配对，但要求是：
我们应该使用数组和循环。
我已经弄清楚了如何在这个项目中使用数组，但我不知道如何插入循环。我尝试在网上搜索示例，但都是关于switch和if else语句的。希望你们能帮我解决这个问题。谢谢。
英文:
I started learning java and im a total newbie. I decided to make Chinese Zodiac signs for my project but the requirements are:
we should use arrays and loops
i already figured out how to use arrays for this project but i dont know how to insert the loops. i tried googling for examples but all are switch and if else statements. hope you guys could help me with this. thanks.
答案1
得分: 1
你创建一个数组。填充它。然后使用从0开始的for循环，因为数组从0开始，并一直进行到数组的最后一个元素。在我的示例中，我有一个包含3个元素的数组，所以我的元素将位于0、1、2位置。zodiacs.length会给我3，所以我从0数到2，包括2。
使用for循环
String zodiacs[] = new String[3];
zodiacs[0] = "Aries";
zodiacs[1] = "Whatever";
zodiacs[2] = "something";
for (int i = 0; i < zodiacs.length; i++) {
System.out.println(zodiacs[i]);
}
使用while循环
String zodiacs[] = new String[3];
zodiacs[0] = "Aries";
zodiacs[1] = "Whatever";
zodiacs[2] = "something";
int i = 0;
while (i < zodiacs.length) {
System.out.println(zodiacs[i]);
i++;
}
由于你不允许使用HashMap，想法是创建两个数组：一个用于年份，一个用于生肖符号。每个生肖符号应该与其代表年份的索引相同。例如，“Whatever”在1992年，所以zodiacs[0]应该是“Whatever”，在years数组中1992应该在years[0]位置。
String zodiacs[] = new String[3];
int years[] = new int[3];
zodiacs[0] = "Aries";
zodiacs[1] = "Whatever";
zodiacs[2] = "something";
years[0] = 1991;
years[1] = 1992;
years[2] = 1993;
int yearUserWasBorn = 1992;
int i = 0;
int zodiacIndexForUserYear = -1;
while (i < years.length) {
if (years[i] == yearUserWasBorn) {
zodiacIndexForUserYear = i;
break;
}
i++;
}
if (zodiacIndexForUserYear == -1) {
System.out.println("Sorry we couldn't find your zodiac based on your year");
} else {
System.out.println("Zodiac is : " + zodiacs[zodiacIndexForUserYear]);
}
英文:
You create array. Populate it. Then use for loop starting at 0 because arrays start at 0 and go until you are at last element of array. In my example I have array with 3 elements so my elements will be at 0,1,2 positions. zodiacs.length will give me 3 so I start counting from 0 to 2 including 2
Using for loop
String zodiacs[] =new String[3];
zodiacs[0] = "Aries";
zodiacs[1] = "Whatever";
zodiacs[2] = "something";
for(int i = 0 ; i < zodiacs.length ; i++) {
System.out.println(zodiacs[i]);
}
Using while loop
String zodiacs[] =new String[3];
zodiacs[0] = "Aries";
zodiacs[1] = "Whatever";
zodiacs[2] = "something";
int i = 0;
while(i < zodiacs.length){
System.out.println(zodiacs[i]);
i++;
}
Since you are not allowed to use HashMap, idea is to create 2 arrays: one for years and one for zodiac signs. Each zodiac sign should be at same index as it's representative year. example "Whatever" is in 1992 so at zodiacs[0] should be "Whatever" and in years 1992 shoud be at years[0]
String zodiacs[] =new String[3];
int years[] =new int[3];
zodiacs[0] = "Aries";
zodiacs[1] = "Whatever";
zodiacs[2] = "something";
years[0] = 1991;
years[1] = 1992;
years[2] = 1993;
int yearUserWasBorn = 1992;
int i = 0;
int zodiacIndexForUserYear = -1;
while(i < years.length){
if(years[i] == yearUserWasBorn){
zodiacIndexForUserYear = i;
break;
}
i++;
}
if(zodiacIndexForUserYear == -1){
System.out.println("Sorry we couldn't find you zodiac based on you year");
}else{
System.out.println("Zodiac is : " + zodiacs[i]);
}
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