英文:
How do I end loop when 0 is entered?
问题
import javax.swing.JOptionPane;
public class MaxMinAvg {
public static void main(String args[]) {
String inString = " ";
int count = 0;
inString = JOptionPane.showInputDialog("Enter a String");
while (inString.length() != 0) {
count++;
System.out.println("record " + count + " is " + inString);
inString = JOptionPane.showInputDialog("Enter a String");
}
System.out.println("All done");
}
}
英文:
I'm writing a program where the user will keep entering numbers until 0 is entered using loops. It will then display the largest number entered, the smallest number entered, and the average of all the numbers. This is what I have to start with:
import javax.swing.JOptionPane;
public class MaxMinAvg
{
public static void main(String args[])
{
String inString = " ";
int count = 0;
inString = JOptionPane.showInputDialog("Enter a String");
//perform until the end of file
while(inString.length() != 0)
{
count++;
System.out.println("record " + count + " is " + inString);
// second read
inString = JOptionPane.showInputDialog("Enter a String");
} // end while loop
System.out.println("All done");
}
}
答案1
得分: 1
尝试将输入字符串与退出条件进行比较：
```java
import javax.swing.JOptionPane;
public class MaxMinAvg
{
public static void main(String args[])
{
String inString = " ";
int count = 0;
inString = JOptionPane.showInputDialog("请输入一个字符串");
while(inString.length() != 0 && !inString.equals("0"))
{
count++;
System.out.println("记录 " + count + " 为 " + inString);
inString = JOptionPane.showInputDialog("请输入一个字符串");
}
System.out.println("全部完成");
}
}
英文:
try to compare the input string with your exit condition:
import javax.swing.JOptionPane;
public class MaxMinAvg
{
public static void main(String args[])
{
String inString = " ";
int count = 0;
inString = JOptionPane.showInputDialog("Enter a String");
//perform until the end of file
while(inString.length() != 0 && !inString.equal("0"))
{
count++;
System.out.println("record " + count + " is " + inString);
// second read
inString = JOptionPane.showInputDialog("Enter a String");
} // end while loop
System.out.println("All done");
}
}
答案2
得分: 0
首先，您不需要两次使用 JOptionPane.showInputDialog("Enter a String");。将其放在 while 循环内部调用一次即可。
其次，定义一个无限的 while 循环 - 使用 while(true)，因为您不知道用户会提供多少次输入。
第三，要在输入为 0 时停止循环，将逻辑放在循环内部。
- 使用
trim()去除输入中的空格，因为用户可能会在数字前后插入空格。 - 将输入转换为
int类型。 - 使用
==检查用户给定的输入是否等于0。 - 使用
break停止循环。
public static void main(String args[]) {
String inString = "";
int count = 0;
while(true) {
inString = JOptionPane.showInputDialog("Enter a String");
count++;
System.out.println("record " + count + " is " + inString);
if (Integer.parseInt(inString.trim()) == 0) {
break;
}
}
System.out.println("All done");
}
英文:
First, you don't need JOptionPane.showInputDialog("Enter a String"); twice. Call it once inside the while loop.
Second, define an infinite while loop - while(true) since you don't know how many times user will give input.
Third, as to stop the loop based on input 0, put the logic inside the loop.
trim()the input, user could insert a blank space before or after the unmber- convert the input into
int - check equality
==of user given input with0 breakthe loop
public static void main(String args[]) {
String inString = "";
int count = 0;
while(true) {
inString = JOptionPane.showInputDialog("Enter a String");
count++;
System.out.println("record " + count + " is " + inString);
if (Integer.parseInt(inString.trim()) == 0) {
break;
}
}
System.out.println("All done");
}
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