英文:
How to determine syllables in a word by using regular expression
问题
给定我有一个故事。这个故事由单词组成。我需要构建一个正则表达式来计算故事中每个单词的音节数。
我试图构建一个正则表达式，满足以下条件：
如果单词以字符'e'结尾
并且单词中至少包含一个元音字符'a'|'e'|'i'|'o'|'u'|'y'
则不要匹配单词末尾的 'e'
但匹配单词中的所有其他元音
如果单词只包含一个独立的'e'，并且在单词末尾
并且单词不包含其他元音字符
则匹配这个独立的 'e'
预期输出：
对于每个单词找到的匹配应该是：
对于 aerospace，有 3 个音节。
对于 she，有 1 个音节。
总共 4 个音节。
我能够构建出 (?(?=([a-zA-Z]+e))(?=([aeiouy])))，但需要你的帮助，如果可能的话，将其合并为单个表达式。
英文:
Given I have a story. The story consists of words. I need to construct a regular expression to count the number of syllables for each word in a story.
I try to construct a regular expression where the following is met:
IF word ends with character 'e'
AND word also contains at least one of the vowel characters 'a'|'e'|'i'|'o'|'u'|'y'
THEN do not match 'e' at the end of word
BUT match all the other vowels in word
IF word contains only a lone 'e' at the end of a word
AND word does not contain other vowel characters
THEN match the lone 'e'
Expected output:
Counting the matches found for each word should result in:
3 syllables for aerospace
1 syllable for she
A total of 4 syllables.
I was able to construct (?(?=([a-zA-Z]+e))(?=([aeiouy]))) but need some help from you to get it done in a single expression if that's possible.
答案1
得分: 0
在阅读了大量有关正则表达式以及正则表达式条件使用的资料之后，我发现 Java 正则表达式包默认不支持条件语句。可以在这里找到答案：https://stackoverflow.com/questions/3687921/conditional-regular-expression-in-java
因此，最终构建了一个不含 if-else-then 条件的正则表达式。
([aeiouyAEIOUY]+[^e.\s])|([aiouyAEIOUY]+\b)|(\b[^aeiouy0-9.']+e\b)
（https://regex101.com/r/gPO6mP/17）
欢迎提出改进意见。
谢谢。
英文:
After reading a lot about Regex and the use of Regex conditions. Conditionals are not supported by default by the Java Regex package. (Found the answer here: https://stackoverflow.com/questions/3687921/conditional-regular-expression-in-java)
So, finally constructed a Regex without if-else-then condition.
([aeiouyAEIOUY]+[^e.\s])|([aiouyAEIOUY]+\b)|(\b[^aeiouy0-9.']+e\b)
(https://regex101.com/r/gPO6mP/17)
Improvements are welcome.
Thanks.
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