随机行走者（圆形）向上移动的频率要比其他轴频繁得多。

huangapple
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英文:

Random Walker (circle) move up much more frequent than other axis

问题

以下是翻译好的内容：

这是我做的一个小项目，只是为了好玩。我尝试使用libgdx在Java中重新创建随机漫步。

现在我认为我的代码相当成功，因为它（可能）正常工作。

但有一个问题，圆圈倾向于比其他轴更频繁地向上移动（沿y轴+方向）。

我已经花了两天时间来找出解决方案。仍然找不出我做错了什么。

以下是代码：

  1. public class MyGdxGame implements ApplicationListener
  2. {
  3.     ShapeRenderer sr;
  4.     OrthographicCamera cam;
  5.     Random r;
  6.     int rand;
  7.     float x;
  8.     float y;
  10.     @Override
  11.     public void create()
  12.     {
  13.         sr = new ShapeRenderer();
  14.         cam = new OrthographicCamera();
  15.         cam.setToOrtho(false, Gdx.graphics.getWidth(), Gdx.graphics.getHeight());
  17.         r = new Random();
  19.         x = Gdx.graphics.getWidth() / 2;
  20.         y = Gdx.graphics.getHeight() / 2;
  21.     }
  23.     @Override
  24.     public void render()
  25.     {
  26.         cam.update();
  28.         rand = r.nextInt(3);
  30.         Gdx.gl.glClearColor(1, 1, 1, 1);
  31.         Gdx.gl.glClear(GL20.GL_COLOR_BUFFER_BIT);
  32.         sr.begin(ShapeRenderer.ShapeType.Filled);
  33.         sr.setColor(Color.RED);
  34.         sr.circle(x, y, 10);
  35.         sr.end();
  37.         switch (rand)
  38.         {
  39.             case 0:
  40.                 x = x + 100 * Gdx.graphics.getDeltaTime();
  41.                 break;
  43.             case 1:
  44.                 x = x - 100 * Gdx.graphics.getDeltaTime();
  45.                 break;
  46.             case 2:
  47.                 y = y + 100 * Gdx.graphics.getDeltaTime();
  48.                 break;
  50.             case 3:
  51.                 y = y - 100 * Gdx.graphics.getDeltaTime();
  52.                 break;
  53.             default:
  55.         }
  56.     }
  57. }
英文:

So this is a little project by me , just for fun. Ive tried recreating random Walker in Java by using libgdx.

Now I consider my code pretty much successful as it's working properly (perhaps).

But there is this one problem, the circle tends to move upward(yaxis+) much more frequent than other axis.

It's been 2 days for me to figure out the solution. Still can't find where did I do wrong.

So here's the code

  1. {
  2. ShapeRenderer sr;
  3. OrthographicCamera cam;
  4. Random r;
  5. int rand;
  6. float x;
  7. float y;
  8. @Override
  9. public void create()
  10. {
  11. sr = new ShapeRenderer();
  12. cam = new OrthographicCamera();
  13. cam.setToOrtho(false, Gdx.graphics.getWidth(), Gdx.graphics.getHeight());
  14. r = new Random();
  15. x = Gdx.graphics.getWidth()/2;
  16. y = Gdx.graphics.getHeight()/2;
  17. }
  18. @Override
  19. public void render()
  20. {        
  21. cam.update();	
  22. rand = r.nextInt(3);
  23. Gdx.gl.glClearColor(1, 1, 1, 1);
  24. Gdx.gl.glClear(GL20.GL_COLOR_BUFFER_BIT);
  25. sr.begin(ShapeRenderer.ShapeType.Filled);
  26. sr.setColor(Color.RED);
  27. sr.circle(x, y, 10);
  28. sr.end();
  29. switch(rand)
  30. {
  31. case 0:
  32. x = x + 100 * Gdx.graphics.getDeltaTime();
  33. break;
  34. case 1:
  35. x = x - 100 * Gdx.graphics.getDeltaTime();
  36. break;
  37. case 2:
  38. y = y + 100 * Gdx.graphics.getDeltaTime();
  39. break;
  40. case 3:
  41. y = y - 100 * Gdx.graphics.getDeltaTime();
  42. break;
  43. default:
  44. }
  45. }```
  46. </details>
  47. # 答案1
  48. **得分**: 1
  49. 所以你在这里的问题是Random.nextInt(n)方法的上限是排除的。
  50. // 返回0-9之间的数字
  51. int next = ran.nextInt(10);
  52. 所以你需要使用
  53. rand = r.nextInt(4);
  54. 你正在生成0->2之间的rand，你需要它是0->3，以包括沿着y轴向下移动。
  55. <details>
  56. <summary>英文:</summary>
  57. So your problem here is the upper bounds on a Random.nextInt(n) method is exclusive
  58. // Returns number between 0-9 
  59. int next = ran.nextInt(10); 
  60. So you need to use 
  61. rand = r.nextInt(4);
  62. What you&#39;re doing is generating rand between 0-&gt;2, you need it to be 0-&gt;3 to include the y axis to go down
  63. </details>

huangapple
  • 本文由 发表于 2020年4月5日 01:25:36
  • 转载请务必保留本文链接：https://go.coder-hub.com/61031984.html
  • android
  • java
  • libgdx
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