如何在抽屉菜单中获取已登录用户的信息?

huangapple go评论85阅读模式
英文:

How to get logged user's information in drawer menu?

问题

我试图从 Firebase 中获取当前用户的用户名和电子邮件,并在抽屉菜单中显示出来。然而,程序崩溃并返回了以下错误:

java.lang.NullPointerException: 尝试在空对象引用上调用虚拟方法 'void android.widget.TextView.setText(java.lang.CharSequence)'
        at com.example.android.myapplication.NavigationActivity$1.onDataChange(NavigationActivity.java:79)

以下是我的导航活动代码部分:

public class NavigationActivity extends AppCompatActivity implements NavigationView.OnNavigationItemSelectedListener{

    // ... (其他代码)

    private void getUserInformation() {
        DatabaseReference userDatabase= FirebaseDatabase.getInstance().getReference().child("users").child(userId);

        userDatabase.addValueEventListener(new ValueEventListener() {
            @Override
            public void onDataChange(@NonNull DataSnapshot dataSnapshot) {
                if (dataSnapshot.exists()) {
                    for (DataSnapshot child : dataSnapshot.getChildren()) {
                        if (child.getKey().equals("name")) {
                            name.setText(child.getValue().toString());
                        }
                        if (child.getKey().equals("email")) {
                            email.setText(child.getValue().toString());
                        }
                    }
                }
            }

            @Override
            public void onCancelled(@NonNull DatabaseError databaseError) {

            }
        });
    }

    // ... (其他代码)
}

这是我的数据库结构截图:

如何在抽屉菜单中获取已登录用户的信息?

我猜测问题可能是因为 NavigationActivity 不是主要活动,然而,即使我将其更改为主要活动,我仍然遇到相同的错误。

英文:

I've tried to retrieve the current user's username and email from firebase and display it in the drawer menu. However, the program crashed and return the error:

java.lang.NullPointerException: Attempt to invoke virtual method 'void android.widget.TextView.setText(java.lang.CharSequence)' on a null object reference
        at com.example.android.myapplication.NavigationActivity$1.onDataChange(NavigationActivity.java:79)

Here is my Navigation Activity

public class NavigationActivity extends AppCompatActivity implements NavigationView.OnNavigationItemSelectedListener{

    protected DrawerLayout drawer;
    private String userId;
    private TextView email,name;
    private DatabaseReference mDatabase;
    private FirebaseAuth mAuth;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_navigation);

        Toolbar toolbar = findViewById(R.id.toolbar);
        setSupportActionBar(toolbar);
        drawer = findViewById(R.id.drawer_layout);
        NavigationView navigationView=findViewById(R.id.nav_view);
        navigationView.setNavigationItemSelectedListener(this);

        ActionBarDrawerToggle toggle = new ActionBarDrawerToggle(this, drawer, toolbar,
                R.string.navigation_drawer_open, R.string.navigation_drawer_close);
        drawer.addDrawerListener(toggle);
        toggle.syncState();

        name = (TextView)findViewById(R.id.name);
        email=(TextView)findViewById(R.id.email);

        mAuth=FirebaseAuth.getInstance();
        userId= mAuth.getCurrentUser().getUid();

        getUserInformation();

    }

    private void getUserInformation() {
        DatabaseReference userDatabase= FirebaseDatabase.getInstance().getReference().child("users").child(userId);

        userDatabase.addValueEventListener(new ValueEventListener() {
            @Override
            public void onDataChange(@NonNull DataSnapshot dataSnapshot) {
                if (dataSnapshot.exists()) {
                    for (DataSnapshot child : dataSnapshot.getChildren()) {
                        if (child.getKey().equals("name")) {//find the child that Equals to start
                            name.setText(child.getValue().toString());
                        }
                        if (child.getKey().equals("email")) {//find the child that Equals to start
                            email.setText(child.getValue().toString());
                        }
                    }
                }
            }

            @Override
            public void onCancelled(@NonNull DatabaseError databaseError) {

            }
        });
    }


    @Override
    public void onBackPressed() {
        if (drawer.isDrawerOpen(GravityCompat.START)) {
            drawer.closeDrawer(GravityCompat.START);
        } else {
            super.onBackPressed();
        }
    }

    @Override
    public boolean onNavigationItemSelected(@NonNull MenuItem item) {
        switch(item.getItemId()){
            case R.id.nav_run:
                Intent intent = new Intent(NavigationActivity.this,running_map.class);
                startActivity(intent);
                finish();
                break;
            case R.id.nav_history:
                Intent intent2 = new Intent(NavigationActivity.this,HistoryActivity.class);
                startActivity(intent2);
                finish();
                break;
            //......
        }
        drawer.closeDrawer(GravityCompat.START);
        return true;
    }
}

Here is my database:
如何在抽屉菜单中获取已登录用户的信息?
I guessed that this is because the NavigationActivity was not the main activity, however, even when I changed it to the main activity, I still got the same error.

答案1

得分: 2

你不需要使用 for 循环:

private void getUserInformation() {
    DatabaseReference userDatabase = FirebaseDatabase.getInstance().getReference().child("users").child(userId);

    userDatabase.addValueEventListener(new ValueEventListener() {
        @Override
        public void onDataChange(@NonNull DataSnapshot dataSnapshot) {
            if (dataSnapshot.exists()) {
                if (dataSnapshot.child("name").getValue(String.class).equals("name")) {
                    name.setText(child.getValue().toString());
                }
                if (dataSnapshot.child("email").getValue(String.class).equals("email")) {
                    email.setText(child.getValue().toString());
                }
            }
        }

        @Override
        public void onCancelled(@NonNull DatabaseError databaseError) {

        }
    });
}

你的引用位于节点 userId,因此要获取详细信息,你不需要进行迭代。

英文:

You dont need the for loop:

    private void getUserInformation() {
        DatabaseReference userDatabase= FirebaseDatabase.getInstance().getReference().child("users").child(userId);

        userDatabase.addValueEventListener(new ValueEventListener() {
            @Override
            public void onDataChange(@NonNull DataSnapshot dataSnapshot) {
                if (dataSnapshot.exists()) {
                        if (dataSnapshot.child("name").getValue(String.class).equals("name")) {//find the child that Equals to start
                            name.setText(child.getValue().toString());
                        }
                        if (dataSnapshot.child("email").getValue(String.class).equals("email")) {//find the child that Equals to start
                            email.setText(child.getValue().toString());
                        }
                    }
            }

            @Override
            public void onCancelled(@NonNull DatabaseError databaseError) {

            }
        });
    }

Your reference is at node userId, therefore to get the details you dont need to iterate.

huangapple
  • 本文由 发表于 2020年3月16日 05:49:40
  • 转载请务必保留本文链接:https://go.coder-hub.com/60698009.html
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定