英文:
Transferring Object with MapStruct via 2 Mappers using Generated Class
问题
- 我有3个类：A，B，C。
- 每个类都有一个ObjectX字段。
- 类A和C还有一个ObjectY字段。
- 类B是自动生成的，我无法修改它。
- 我有从A到B的映射器，以及从B到C的映射器，它们都不包括ObjectY（它被忽略）。
是否有可能以某种方式修改这些映射器，以便包括ObjectY（而无需添加从A到C的映射）？
映射器代码如下：
@Mapper
public interface MyMapper {
@Mapping(target = "ObjectX")
B AtoB(A a);
@Mapping(target = "ObjectX")
C BtoC(B b);
}
英文:
- I have 3 Classes: A, B, C.
- Each of them has single ObjectX field.
- Classes A and C have also ObjectY field.
- Class B is auto-generated, I can't modify it.
- I have mapper from A to B, and mapper from B to C, they don't
include ObjectY (it is ignored).
Is it possible somehow to modify these mappers in order to include ObjectY (without adding mapping between A to C)?
mapper code is below:
@Mapper
public interface MyMapper {
@Mapping(target = "ObjectX")
B AtoB(A a);
@Mapping(target = "ObjectX")
C BtoC(B b);
}
答案1
得分: 1
如果我理解问题正确，您想将 A 转换为 B，然后将 B 转换为 C，并且您还想保留 ObjectY 字段。
问题在于 B 没有 ObjectY 字段，因此无法通过此转换来存储其值。
我脑海中浮现的唯一解决方案是创建一个类 MyB，它继承自类 B，并包含 ObjectY 字段，然后像这样更改您的映射器：
public class MyB extends B {
private ObjectY objectY;
// 为简洁起见省略了 getter 和 setter 方法
}
@Mapper
public interface MyMapper {
MyB AtoB(A a);
C BtoC(MyB b);
}
但我不确定在您的用例中是否可行。
英文:
If I understand the question correctly, you want to translate A to B and then B to C and you also want to keep ObjectY field.
The problem is that B don't have the ObjectY field, so it cannot store the value of it through this translation.
Only solution which comes to my mind is to create class MyB which extends class B and contains ObjectY field and then change your mapper like this:
public class MyB extends B {
private ObjectY objectY;
// getters and setters omitted for brevity
}
@Mapper
public interface MyMapper {
MyB AtoB(A a);
C BtoC(MyB b);
}
But I'm not sure if it is possible in your use case.
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