Fast way to read file from input stream when we know the size with low memory usage

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英文:

Fast way to read file from input stream when we know the size with low memory usage

问题

以下是翻译好的部分:

当我们知道数据的大小时,是否有更快的方法从InputStream中读取数据?我拥有的这段代码速度非常慢:

File file = new File("file.jar");

if (!file.exists()) file.createNewFile();
String url = "https://launcher.mojang.com/v1/objects/3870888a6c3d349d3771a3e9d16c9bf5e076b908/client.jar";
int len = 8461484;

InputStream is = new URL(url).openStream();

if (!file.exists())
    file.createNewFile();

PrintWriter writer = new PrintWriter(file);

for (long i = 0; i < len; i++) {
    writer.write(is.read());
    writer.flush();
    System.out.println(i);
}
writer.close();
英文:

Is there any faster way to read from an inputstream when we know the size of the data?
This code that I have is very slow:

File file = new File(&quot;file.jar&quot;);

if(!file.exists)file.createNewFile();
String url = &quot;https://launcher.mojang.com/v1/objects/3870888a6c3d349d3771a3e9d16c9bf5e076b908/client.jar&quot;;
int len = 8461484;

InputStream is = new URL(url).openStream();
	
if(!file.exists())
	file.createNewFile();

PrintWriter writer = new PrintWriter(file);

for(long i = 0;i &lt; len;i ++) {
	writer.write(is.read());
	writer.flush();
	System.out.println(i);
}
writer.close();

答案1

得分: 0

使用带有try-with-resources的缓冲输入和输出流<br>
(这确保了流在结束时都被关闭)<br>
类似这样:

try (final InputStream ist = new URL(url).openStream();
    final InputStream bis = new BufferedInputStream(ist);
    
    final OutputStream ost = new FileOutputStream(file);
    final OutputStream bos = new BufferedOutputStream(ost)) {
    final byte[] bytes = new byte[64_000]; // &lt;- 尽可能大!
    /**/  int    count;
    
    while ((count = bis.read(bytes)) != -1) {
        bos.write(bytes, 0, count);
    }
}
英文:

Use Buffered Input & Output Streams together with try-with-resources<br>
(which ensures the Streams are all closed at EOJ)<br>
Something like this:

try(final InputStream  ist = new URL(url).openStream ();
	final InputStream  bis = new BufferedInputStream (ist);

	final OutputStream ost = new     FileOutputStream(file);
	final OutputStream bos = new BufferedOutputStream(ost))
{
	final byte[] bytes = new byte[64_000]; // &lt;- as large as possible!
	/**/  int    count;

	while ((count = bis.read(bytes)) != -1) {
		bos.write(bytes, 0, count);
	}
}

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  • 本文由 发表于 2020年3月4日 05:31:09
  • 转载请务必保留本文链接:https://go.coder-hub.com/60515829.html
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