Jupyter Notebook 异步函数

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英文:

Jupyter Notebook Async functions

问题

以下是您要翻译的内容:

在下面的代码中我希望出现以下行为

当用户单击我在App Mode中定义的按钮时我希望其中的print_async例程被调用它会等待2秒然后打印这是来自buttonCLicked的异步打印”,然后我希望出现按钮已点击!”的打印但实际上我得到了一个解释器错误

任何帮助都将不胜感激

**File "cell_name", line 6
SyntaxError: 'await' outside async function**

from IPython.display import display
from ipywidgets import widgets
import asyncio
#不要更改此单元格
#定义一个异步函数
async def print_async(message):
    await asyncio.sleep(2)
    print(message)
# 显示我们可以从顶级jupyter终端打印
await print_async("这是顶级异步打印")
#为按钮定义回调函数
def onButtonClicked(_):
    await print_async("这是来自buttonCLicked的异步打印")
    print("按钮已点击!")

button = widgets.Button(
    description='点击我',
    disabled=False,
    button_style='', # 'success', 'info', 'warning', 'danger'或''
    tooltip='点击我',
    icon=''
)

button.on_click(onButtonClicked)
display(button)

button = widgets.Button(
    description='点击我',
    disabled=False,
    button_style='', # 'success', 'info', 'warning', 'danger'或''
    tooltip='点击我',
    icon=''
)

button.on_click(onButtonClicked)
display(button)
目标使按钮单击调用print_async方法

请注意,我已经将代码部分排除在翻译之外,只翻译了文本内容。

英文:

In the code below, I'd like the following behavior:

When the user clicks the button I've defined in App Mode, I want the print_async routine inside of it to be invoked, which waits for 2 seconds and then prints ""this is async print from buttonCLicked", then I want the print after which is "button clicked!" to appear. Instead what I get is an interpreter error:

Any help appreciated.

File "cell_name", line 6
SyntaxError: 'await' outside async function

from IPython.display import display
from ipywidgets import widgets
import asyncio
#DO NOT CHANGE THIS CELL
#Define an async function
async def print_async(message):
    await asyncio.sleep(2)
    print(message)
# Show that we can print from the top-level jupyter terminal
await print_async("This is a top-level async print")
#Define a callback function for the button
def onButtonClicked(_):
    await print_async("this is async print from buttonCLicked")
    print("button clicked!")

button = widgets.Button(
    description='Click me',
    disabled=False,
    button_style='', # 'success', 'info', 'warning', 'danger' or ''
    tooltip='Click me',
    icon=''
)

button.on_click(onButtonClicked)
display(button)
​
button = widgets.Button(
    description='Click me',
    disabled=False,
    button_style='', # 'success', 'info', 'warning', 'danger' or ''
    tooltip='Click me',
    icon=''
)
​
button.on_click(onButtonClicked)
display(button)
Goal: Get the button click to call the print_async method

答案1

得分: 1

你可以使用asyncio.run函数来实现这个(需要Python 3.7或更新版本):

在你的代码中,它会像这样:

def onButtonClicked(_):
    asyncio.run(print_async("这是来自按钮点击的异步打印"))
    print("按钮被点击了!")
英文:

You can do this with the asyncio.run function (Requires Python 3.7 or newer):

In your code it would look like this:

def onButtonClicked(_):
    asyncio.run(print_async("this is async print from buttonCLicked"))
    print("button clicked!")

答案2

得分: 0

首先,你不能在异步函数外部使用await关键字。如果这是你异步程序的入口点,可以使用asyncio.run()函数,并将要运行的协程函数作为参数传递给run()方法来调用该协程。

英文:

First of all, You cannot use await keyword outside async function. If that is the entry point to your asynchronous program, use asyncio.run() function with function call as a parameter to run() method to call that co-routine.

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  • 本文由 发表于 2020年1月7日 02:43:05
  • 转载请务必保留本文链接:https://go.coder-hub.com/59617325.html
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