Python解包列表以在格式化字符串中使用

huangapple
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英文:

Python unpack list for use in formatted string

问题

我有一个字符串，根据用户输入动态创建。我在Python中使用.format函数将一个列表添加到字符串中，但我想在打印时删除引号和括号。

我尝试过:

  1. return ((‘{} is {}x effective against {}’).format(opponentType, overallHitMultiplier, [str(x) for x in playerTypes]))

和

  1. return return ((‘{} is {}x effective against {}’).format(opponentType, overallHitMultiplier, playerTypes))

这两者都返回一个字符串，看起来像这样:

  1. fighting is 2x effective against [‘normal’, ‘ghost’]

但我想要的是返回类似这样的内容:

  1. fighting is 2x effective against normal, ghost

列表的长度是可变的，所以我不能逐个插入列表元素。

英文:

I have a string that I am dynamically creating based off user input. I am using the .format function in Python to add a list into the string, but I would like to remove the quotes and brackets when printing.

I have tried: <br>

  1. return ((&#39;{} is {}x effective against {}&#39;).format(opponentType, overallHitMultiplier, [str(x) for x in playerTypes]))

and

  1. return return ((&#39;{} is {}x effective against {}&#39;).format(opponentType, overallHitMultiplier, playerTypes))

which both return a string that looks like this:

fighting is 2x effective against [&#39;normal&#39;, &#39;ghost&#39;]

but I would like it to return something like:

fighting is 2x effective against normal, ghost

The length of the list is variable so I can't just insert the list elements one by one.

答案1

得分: 2

以下是翻译好的内容：

  1. 这是一个更完整的响应：
  3. def convert_player_types_to_str(player_types):
  4.     n = len(player_types)
  5.     if not n:
  6.         return ''
  7.     if n == 1:
  8.         return player_types[0]
  9.     return ', '.join(player_types[:-1]) + f' 和 {player_types[-1]}'
  11. >>> convert_player_types_to_str(['normal'])
  12. 'normal'
  14. >>> convert_player_types_to_str(['normal', 'ghost'])
  15. 'normal 和 ghost'
  17. >>> convert_player_types_to_str(['normal', 'ghost', 'goblin'])
  18. 'normal, ghost 和 goblin'
英文:

Here is a more complete response:

  1. def convert_player_types_to_str(player_types):
  2.     n = len(player_types)
  3.     if not n:
  4.         return &#39;&#39;
  5.     if n == 1:
  6.         return player_types[0]
  7.     return &#39;, &#39;.join(player_types[:-1]) + f&#39; and {player_types[-1]}&#39;
  9. &gt;&gt;&gt; convert_player_types_to_str([&#39;normal&#39;])
  10. &#39;normal&#39;
  12. &gt;&gt;&gt; convert_player_types_to_str([&#39;normal&#39;, &#39;ghost&#39;])
  13. &#39;normal and ghost&#39;
  15. &gt;&gt;&gt; convert_player_types_to_str([&#39;normal&#39;, &#39;ghost&#39;, &#39;goblin&#39;])
  16. &#39;normal, ghost and goblin&#39;

huangapple
  • 本文由 发表于 2020年1月7日 02:13:24
  • 转载请务必保留本文链接：https://go.coder-hub.com/59616943.html
  • python
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