英文:
Counting the number of elements in a list and then taking the counting as a list in R
问题
I have a vector:
x <- c(0.8,1.0,661.7,661.8,661.9,662.3,662.6,662.7,663.3,663.6,663.7)
I have used function as.data.frame(x) to make the following data frame:
X1
1 0.8
2 1.0
3 661.7
4 661.8
5 661.9
6 662.3
7 662.6
8 662.7
9 663.3
10 663.6
11 663.7
How can I take the list of labels for each element?
i.e x0 <- c(1,2,3,4,5,6,7,8,9,10,11)
英文:
I have a vector:
x <- c(0.8,1.0,661.7,661.8,661.9,662.3,662.6,662.7,663.3,663.6,663.7)
I have used function as.data.frame(x) to make following data frame:
X11 0.82 1.03 661.74 661.85 661.96 662.37 662.68 662.79 663.310 663.611 663.7
How can I take the list of labels for each element?
i.e x0 <- c(1,2,3,4,5,6,7,8,9,10,11)
答案1
得分: 2
我们可以有一个名为vector的变量，并使用stack，这也可以灵活地具有不同的标签。
或者使用rownames_to_column：
library(dplyr)as.data.frame(x) %>%rownames_to_column('rn')
英文:
We can have a named vector and use stack and this is also flexible in having different labels
stack(setNames(x, seq_along(x)))
Or using rownames_to_column
library(dplyr)as.data.frame(x) %>%rownames_to_column('rn')
答案2
得分: 1
If you already created that dataframe, take out the rownames:
x <- c(0.8,1.0,661.7,661.8,661.9,662.3,662.6,662.7,663.3,663.6,663.7)rownames(as.data.frame(x))#> [1] "1" "2" "3" "4" "5" "6" "7" "8" "9" "10" "11"
英文:
If you already created that dataframe, take out the rownames:
x <- c(0.8,1.0,661.7,661.8,661.9,662.3,662.6,662.7,663.3,663.6,663.7)rownames(as.data.frame(x))#> [1] "1" "2" "3" "4" "5" "6" "7" "8" "9" "10" "11"
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