英文:
Print multiples of a number less than a given max
问题
打印小于m的n的倍数。
def print_multiples(n, max):
while n <= max:
a = range(n, (n*max)+1, n)
print(*a)
print_multiples(4, 18)
因此，这个示例只会打印：
4
8
12
16
每个答案都在新的一行上。
英文:
Print multiples of n that are less than m.
def print_multiples(n, max):
while n <= max:
a = range(n, (n*max)+1,n)
print(*a)
print_multiples(4, 18)
so this example would only print
4
8
12
16
and each answer is on a new line.
答案1
得分: 0
这段代码将实现您想要的功能。它将最大数除以因子以获取最大的第二因子（//向下取整），然后加一，因为这是范围。然后它将遍历每个第二因子并打印出它们的倍数。
def print_multiples(n, m):
for x in range(1, m//n + 1):
print(x*n)
print_multiples(4, 18)
此外，您应该避免将max用作变量名，因为它是max()函数的关键字。
英文:
This code will do what you want. It divides the maximum number by the factor to get the maximum second factor (// rounds down) and then adds one because it is range. Then it will iterate through each of the second factors and print out the multiples.
def print_multiples(n, m):
for x in range(1, m//n + 1):
print(x*n)
print_multiples(4, 18)
Also, you should avoid using max as a variable name because it is a keyword for the max() function
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