英文:
All matches in a line : Spacy matcher
问题
I am looking for a solution to print all the matching in a line using Spacy matcher.
The example goes like this,
Here I am trying to extract experience.
doc = nlp("1+ years of experience in XX, 2 years of experiance in YY")
pattern = [{'POS': 'NUM'}, {'ORTH': '+', "OP": "?"}, {"LOWER": {"REGEX": "years?|months?"}}]
matcher = Matcher(nlp.vocab)
matcher.add("Skills", None, pattern)
matches = matcher(doc)
print([doc[matches[0][1]:matches[0][2]], doc[matches[1][1]:matches[1][2]]])
Here I am getting output [1+ years, 2 years].
英文:
I am looking for a solution to print all the matching in a line using Spacy matcher
The example goes like this,
Here I am trying to extract experience.
doc = nlp("1+ years of experience in XX, 2 years of experiance in YY")
pattern = [{'POS': 'NUM'}, {'ORTH': '+', "OP": "?"}, {"LOWER": {"REGEX": "years?|months?"}}]
matcher = Matcher(nlp.vocab)
matcher.add("Skills", None, pattern)
matches = matcher(doc)
pirnt(doc[matches[0][1]:matches[0][2]]
Here I am getting output 1+ years.
But I am looking for a solution having output
['1+ years','2 years']
答案1
得分: 2
以下是已经翻译好的内容：
你应该将第一个项目指定为 LIKE_NUM: True：
pattern = [{'LIKE_NUM': True}, {'ORTH': '+', "OP": '?'}, {"LOWER": {"REGEX": "(?:year|month)s?"}}]
我还将 years?|months? 缩写为 (?:year|month)s?，你甚至可以考虑使用 ^(?:year|month)s?$ 来匹配完整的标记字符串，但在这一点上这不是必要的。
代码：
import spacy
from spacy.matcher import Matcher
nlp = spacy.load("en_core_web_sm")
matcher = Matcher(nlp.vocab)
pattern = [{'LIKE_NUM': True}, {'ORTH': '+', "OP": '?'}, {"LOWER": {"REGEX": "(?:year|month)s?"}}]
matcher.add("Skills", None, pattern)
doc = nlp("1+ years of experience in XX, 2 years of experiance in YY")
matches = matcher(doc)
for _, start, end in matches:
print(doc[start:end].text)
输出：
1+ years
2 years
英文:
You should specify the first item as 'LIKE_NUM': True:
pattern = [{'LIKE_NUM': True}, {'ORTH': '+', "OP": "?"}, {"LOWER": {"REGEX": "(?:year|month)s?"}}]
I also contracted the years?|months? to (?:year|month)s?, you might even consider matching full token string using ^(?:year|month)s?$, but that is not necessary at this point.
Code:
import spacy
from spacy.matcher import Matcher
nlp = spacy.load("en_core_web_sm")
matcher = Matcher(nlp.vocab)
pattern = [{'LIKE_NUM': True}, {'ORTH': '+', "OP": "?"}, {"LOWER": {"REGEX": "(?:year|month)s?"}}]
matcher.add("Skills", None, pattern)
doc = nlp("1+ years of experience in XX, 2 years of experiance in YY")
matches = matcher(doc)
for _, start, end in matches:
print(doc[start:end].text)
Output:
1+ years
2 years
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