how get first row from duplicata values Oracle SQL query

Below you can find my table with values (there are no constraints on my table):

SELECT DISTINCT * FROM khalil;

outputs:

>
> ID VALUE
> -- -------
> 1 yassine
> 1 khalil
> 2 amine
>

I need to get the first row when I have duplicate values.

I have two rows with id = 1 so, in this case, I need that the first one,
which is id = 1 and value = 'yassine'

SELECT * FROM khalil
WHERE ROWID IN (SELECT MIN(ROWID) FROM khalil GROUP BY id)
ORDER BY id

This will return the first row for each id.

If you don't really care which value you'll get (unless there's something you can use to distinguish values), aggregates - such as min or max - can help:

SQL> select id,
  2         max(value) value
  3  from khalil
  4  group by id
  5  order by id;
        ID VALUE
---------- --------------------
         1 yassine
         2 amine
SQL>

Alternatively, using analytic functions (such as row_number, which lets you sort values), you'd do it as follows:

SQL> with temp as
  2    (select id,
  3            value,
  4            row_number() over (partition by id order by value desc) rn
  5     from khalil
  6    )
  7  select id,
  8         value
  9  from temp
 10  where rn = 1
 11  order by id;
        ID VALUE
---------- --------------------
         1 yassine
         2 amine
SQL>