Firebase在Android上:DataSnapshot.getValue()会导致当前活动结束。

huangapple go评论69阅读模式
英文:

Firebase on Android : DataSnapshot.getValue() causes current activity to end

问题

这是我的用户类:

public class User {

    public String name;
    public int number;
    public String title;
    public String company;
    public String location;
    public Bitmap image;
    public String name_title_company_location;
    public static int uid = 0;

    public User() {
        // DataSnapshot.getValue(User.class) 需要默认构造函数
    }

    public User(String name, int number, String title, String company, String location, Bitmap image) {
        this.name = name;
        this.number = number;
        this.title = title;
        this.company = company;
        this.location = location;
        this.image = image;
        this.name_title_company_location = name + "_" + title + "_" + company + "_" + location;
        uid++;
    }
}

这是我的Firebase数据库:

users
    1
        company: "Indifair"
        image
        location: "Bangalore"
        name: "Anupam Singh"
        name_title_company_location: "Anupam Singh_Engineer_Indifair_Bangalore"
        number: 956156494
        title: "Engineer"

我正在使用以下代码从数据库中读取数据:

public class QueryActivity extends AppCompatActivity {

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_query);

        Button bt = (Button) findViewById(R.id.button3);

        bt.setOnClickListener(new View.OnClickListener() {

            @Override
            public void onClick(View v) {
                DatabaseReference mDatabase = FirebaseDatabase.getInstance().getReference();
                EditText t1 = (EditText) findViewById(R.id.editText10);
                EditText t2 = (EditText) findViewById(R.id.editText11);
                EditText t3 = (EditText) findViewById(R.id.editText13);
                EditText t4 = (EditText) findViewById(R.id.editText14);

                final String s1 = t1.getText().toString();
                final String s2 = t2.getText().toString();
                final String s3 = t3.getText().toString();
                final String s4 = t4.getText().toString();

                mDatabase.child("users").orderByChild("name_title_company_location")
                        .equalTo(s1 + "_" + s2 + "_" + s3 + "_" + s4)
                        .addValueEventListener(new ValueEventListener() {
                            @Override
                            public void onDataChange(DataSnapshot dataSnapshot) {
                                for (DataSnapshot userSnapshot : dataSnapshot.getChildren()) {
                                    User user = userSnapshot.getValue(User.class);
                                }
                            }

                            public void onCancelled(DatabaseError databaseError) {
                                // 在Logcat中没有错误或异常信息
                            }
                        });
            }
        });
    }
}

当我点击按钮3时,当前活动结束,控制权返回到父活动。如果我将以下行注释掉:

User user = userSnapshot.getValue(User.class);

问题就消失了。

build.gradle中,我已经添加了正确的依赖项。

可能出了什么问题?

英文:

This is my user class :

public class User {
public String name;
public int number;
public String title;
public String company;
public String location;
public Bitmap image;
public String name_title_company_location;
public static int uid = 0;
public User() {
// Default constructor required for calls to DataSnapshot.getValue(User.class)
}
public User(String name, int number, String title, String company, String location, Bitmap image) {
this.name = name;
this.number = number;
this.title = title;
this.company = company;
this.location = location;
this.image = image;
this.name_title_company_location = name + "_" + title + "_" +company + "_" + location;
uid++;
}

}

This is my Firebase databse :

 users
1
company:"Indifair"
image
location:"Bangalore"
name:"Anupam Singh"
name_title_company_location:"Anupam Singh_Engineer_Indifair_Bangalore"
number:956156494
title:"Engineer"

I am using this code to read from database :

            public class QueryActivity extends AppCompatActivity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_query);
Button bt = (Button) findViewById(R.id.button3);
bt.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
DatabaseReference mDatabase = FirebaseDatabase.getInstance().getReference();
EditText t1 = (EditText) findViewById(R.id.editText10);
EditText t2 = (EditText) findViewById(R.id.editText11);
EditText t3 = (EditText) findViewById(R.id.editText13);
EditText t4 = (EditText) findViewById(R.id.editText14);
final String s1 = t1.getText().toString();
final String s2 = t2.getText().toString();
final String s3 = t3.getText().toString();
final String s4 = t4.getText().toString();
mDatabase.child("users").orderByChild("name_title_company_location")
.equalTo(s1 + "_" + s2 + "_" + s3 + "_" + s4)
.addValueEventListener(new ValueEventListener() {
@Override
public void onDataChange(DataSnapshot dataSnapshot) {
for (DataSnapshot userSnapshot : dataSnapshot.getChildren()) {
User user = userSnapshot.getValue(User.class);
}
}
public void onCancelled(DatabaseError databaseError) {
// Getting Post failed, log a message
//Log.w(TAG, "loadPost:onCancelled", databaseError.toException());
}
});
}
});
}
}

When I click button3 current activity ends and control goes to parent activity. If I comment out

  User user = userSnapshot.getValue(User.class); 

the problem is gone.

There is no error or exception in Logcat. I have added correct dependencies in build.gradle.

What could be going wrong?

答案1

得分: 1

我认为用户类应该扩展到某个类。例如,`public User extends.....() {
// DataSnapshot.getValue(User.class)所需的默认构造函数
}

public User(String name, int number, String title, String company, String location, Bitmap image) {
this.name = name;
this.number = number;.....`

英文:

I thought the user class should extend to something. e.g `public User extends.....() {
// Default constructor required for calls to DataSnapshot.getValue(User.class)
}

public User(String name, int number, String title, String company, String location, Bitmap image) {
this.name = name;
this.number = number;.....`

huangapple
  • 本文由 发表于 2020年1月6日 21:37:44
  • 转载请务必保留本文链接:https://go.coder-hub.com/59613115.html
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定