英文:
Reshape a variable numpy array
问题
假设我有一个形状已知的NumPy数组u，以及u中总条目数的除数d。如何快速地将u重新塑造为形状为(something,d)的数组？
当u只是一个双精度数时，也应包括在内 -> (1,1)。
当u为空时，应变成一个形状为(0,d)的数组。
英文:
Suppose i have a numpy array u with a given shape, a a divisor d of the total number of entries in u. How can i fastly reshape u to be shaped (something,d) ?
The case where u is just a double should be included as well -> (1,1)
The case where u is empty should become a (0,d) shaped array
答案1
得分: 1
你想要使用reshape
u.reshape(-1, d)
Python 中没有double，你是不是想说float？
简而言之：
import numpy as np
def div_reshape(arr, div):
if arr.size == 0:
return np.empty(shape=(0, div))
elif arr.size == 1:
return arr.reshape(1, 1)
else:
return arr.reshape(-1, d)
英文:
You want to use reshape
u.reshape(-1, d)
There is no double in Python you do you mean float ?
In short :
import numpy as np
def div_reshape(arr, div):
if arr.size == 0:
return np.empty(shape=(0, div))
elif arr.size == 1:
return arr.reshape(1, 1)
else:
return arr.reshape(-1, d)
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