英文:
How to group by 4 elements
问题
以下是您要求的翻译：
基本上有4个元素按顺序排列，我需要粘贴成4个一组我的输入hr avg(total) avg(rate1) avg(rate2)036.270.3735.9173.2611.761.56期望输出hr avg(total) avg(rate1) avg(rate2)0 36.27 0.37 35.91 73.26 11.7 61.56
英文:
Basically 4 elements are there in order, i need to paste in group of 4
My input
hr avg(total) avg(rate1) avg(rate2)036.270.3735.9173.2611.761.56
Expected out
hr avg(total) avg(rate1) avg(rate2)0 36.27 0.37 35.91 73.26 11.7 61.56
答案1
得分: 1
如果您想在不使用pandas的情况下解决问题，您可以使用以下示例（txt是包含来自您的问题的文本的变量）：
from io import StringIOfrom itertools import groupbyreader = StringIO(txt)# 读取标题vals = [next(reader).split()]# 读取其余部分for _, g in groupby(enumerate(reader), lambda k: k[0] // len(vals[0])):vals.append([val.strip() for _, val in g])for line in vals:print(*line, sep='\t')
打印输出：
hr avg(total) avg(rate1) avg(rate2)0 36.27 0.37 35.91 73.26 11.7 61.56
英文:
If you want solution without pandas, you can use this example (txt is variable containing text from your question):
from io import StringIOfrom itertools import groupbyreader = StringIO(txt)# read headersvals = [next(reader).split()]# read the restfor _, g in groupby(enumerate(reader), lambda k: k[0] // len(vals[0])):vals.append([val.strip() for _, val in g])for line in vals:print(*line, sep='\t')
Prints:
hr avg(total) avg(rate1) avg(rate2)0 36.27 0.37 35.91 73.26 11.7 61.56
答案2
得分: 0
print("hr", "avg(total)", "avg(rate1)", "avg(rate2)")print("{}\t{}\t{}\t{}".format(0, 36.27, 0.37, 35.9))print("{}\t{}\t{}\t{}".format(1, 73.26, 11.7, 61.56))
output:hr avg(total) avg(rate1) avg(rate2)0 36.27 0.37 35.91 73.26 11.7 61.56
英文:
code:
print("hr","avg(total)","avg(rate1)","avg(rate2)")print("{}\t{}\t{}\t{}".format(0,36.27,0.37,35.9))print("{}\t{}\t{}\t{}".format(1,73.26,11.7,61.56))
output:
hr avg(total) avg(rate1) avg(rate2)0 36.27 0.37 35.91 73.26 11.7 61.56
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