如何在Firestore中获取引用数组?

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英文:

How to get an array of references in Firestore?

问题

我在Firestore的聊天集合中有以下结构:

chats: [
    chat1: { 
        jobs: [
            jobs/job1,
            jobs/job2,
            jobs/job4
        ]
    },
    chat2: { 
        jobs: [
            jobs/job2,
            jobs/job3
        ]
    }
]

如果我在chat1上,并且我有数据,那么我有对作业的引用数组。我知道我有jobs/job1jobs/job2jobs/job4

我如何查询并获取所有这些作业的数据?

我可以这样做:

firestore.doc("jobs/job1").get()firestore.doc("jobs/job2").get()firestore.doc("jobs/job3").get(),但这似乎非常低效。

我不明白如何筛选firestore.collection("jobs")以获取我想要的内容。

我看到有一些其他问题在这里提出了相同的问题,但是针对Java,我无法将其翻译成JavaScript。

英文:

I have the following structure in Firestore for my chats collection:

chats: [
    chat1: { 
        jobs: [
            jobs/job1,
            jobs/job2,
            jobs/job4
        ]
    },
    chat2: { 
        jobs: [
            jobs/job2,
            jobs/job3
        ]
    }
]

If I'm on chat1, and I have the data, then I have the array of references to jobs. I know I have jobs/job1, jobs/job2 and jobs/job4.

How can I query and get the data for all of these jobs?

I could do:
firestore.doc("jobs/job1").get() and firestore.doc("jobs/job2").get() and firestore.doc("jobs/job3").get() but that seems very inefficient.

And I don't understand how I can filter firestore.collection("jobs") to give me what I want.

I've seen a few other questions here asking the same thing, but for Java, and I'm unable to translate it into JavaScript.

答案1

得分: 2

> 我可以这样做:firestore.doc("jobs/job1").get() 和 firestore.doc("jobs/job2").get() 以及 firestore.doc("jobs/job3").get(),但这似乎非常低效。

这正是你想要做的 - 你可以迭代列表并单独获取每个文档。Firestore 并没有提供一种优化的方式来在一个查询中 使用 web 和移动 SDKs 获取多个文档 - 仅仅使用自己的查询来获取每个文档就足够高效了。你不会遇到任何问题。

另请参阅:https://stackoverflow.com/q/46721517

英文:

> I could do: firestore.doc("jobs/job1").get() and firestore.doc("jobs/job2").get() and firestore.doc("jobs/job3").get() but that seems very inefficient.

That's exactly what you want to do - you can iterate the list and get each document individually. Firestore doesn't offer some optimized way to get multiple documents in one query using the web and mobile SDKs - it's plenty efficient just to get each one using its own query. You won't have any problems with this approach.

See also: https://stackoverflow.com/q/46721517

答案2

得分: 0

import { deleteDoc, collection, doc, query, getDocs, setDoc } from "firebase/firestore"

const q = query(collection(db, 'collection_name'))
const querySnap = await getDocs(q)
querySnap.forEach((doc) => {

    console.log("querySnap data", doc.data())
    // reference is accessed as doc.ref
    // if u wish u can push them to an array like myDocRefs.push(doc.ref)

    console.log("querySnap data", doc.ref)

})
英文:
 import { deleteDoc, collection, doc, query, getDocs, setDoc } from "firebase/firestore"

const q = query(collection(db, 'collection_name'))
const querySnap = await getDocs(q)
querySnap.forEach((doc) => {

        console.log("querySnap data", doc.data())
        // reference is accessed as doc.ref
        // if u wish u can push them to an array like myDocRefs.push(doc.ref)


        console.log("querySnap data", doc.ref)

    })

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  • 本文由 发表于 2020年1月6日 19:30:23
  • 转载请务必保留本文链接:https://go.coder-hub.com/59611343.html
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