英文:
Get permutations from 2 vectors in Netlogo
问题
我有2个向量，例如
设置 xlims [0 9]
设置 ylims [0 9]
并希望得到一个列表中的排列组合：
[ [0 0] [9 0] [0 9] [9 9] ]
我一直尝试使用 foreach 但没有成功。
如何编写这段代码？
英文:
I have 2 vectors, say
set xlims [0 9]
set ylims [0 9]
and want to get the permutations in a list:
[ [0 0] [9 0] [0 9] [9 9] ]
I have been trying foreach to no avail.
How can this be coded?
答案1
得分: 1
一个嵌套的foreach会给你想要的结果。
to-report permute [ lst1 lst2 ]
let result []
foreach lst1 [l1 ->
foreach lst2 [l2 ->
set result lput (list l1 l2) result
]
]
report result
end
permute [0 9] [0 9] 得到 [[0 0] [0 9] [9 0] [9 9]]，
而 permute [0 9] [0 9 1] 得到 [[0 0] [0 9] [0 1] [9 0] [9 9] [9 1]]
如果你想用超过两个列表来做这个操作，你可能需要使用递归解决方案。
英文:
A nested foreach will give you what you want.
to-report permute [ lst1 lst2 ]
let result []
foreach lst1 [l1 ->
foreach lst2 [l2 ->
set result lput (list l1 l2) result
]
]
report result
end
permute [0 9] [0 9] yields [[0 0] [0 9] [9 0] [9 9]]
and permute [0 9] [0 9 1] yields [[0 0] [0 9] [0 1] [9 0] [9 9] [9 1]]
If you want to do this with more than two lists, you'll likely want a recursive solution.
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