英文:
face issues in loop and break in php
问题
以下是您要的翻译部分：
我在我的简单代码中遇到了无法解决的问题foreach(file('num.txt') as $num) {foreach(file('char.txt') as $char) {echo $char.$num. "<br>";if($char=="C"&&$num==3){echo 'Found it<br>';break;}}echo '----------------------------<br>';}num.txt 包含如下数字12345 每行一个char 包含字符 A B C D 每行一个.结果是在 break 后的文本中没有删除 C3但我想要的是这种方式，不包括找到的 C3A1B1C1D1--------------A2B2C2D2--------------A3B3C3Found itD3--------------A4B4D4--------------A5B5D5--------------所以 C 不再在循环中，并且如果添加 B5 等，继续下去请帮忙，我需要完成这个任务
希望这有助于您理解代码问题并解决它。
英文:
I've faced problem that I cant resolve in my simple code
foreach(file('num.txt') as $num) {foreach(file('char.txt') as $char) {echo $char.$num. "<br>";if($char=="C"&&$num==3){echo 'Found it<br>';break;}}echo '----------------------------<br>';}
num.txt contains numbers like this
1
2
3
4
5 per line
char contains character Like A B C D per line
.
and as result
it dose not remove the C3 in text step after break
but i want it like this way without the founded C3
A1B1C1D1--------------A2B2C2D2--------------A3B3C3Found itD3--------------A4B4D4--------------A5B5D5--------------
so C is no longer in the loop and continue if add B5 and so on
Please help i need this assignment
答案1
得分: 0
如果您有一个常规的数组，您可以从中移除 "C"，但由于您从文件中隐式获取数据，这是解决方案。不是最优雅的方法，但可以工作：
// 添加一个标志以表示找到的值$found = false;foreach(file('num.txt') as $num) {foreach(file('char.txt') as $char) {// 条件来显示一个条目if(!$found || $char != "C") {echo $char . $num . "<br>";if($char == "C" && $num == 3) {echo '找到了<br>';// 您不需要 'break'，删除它并设置标志$found = true;}}}echo '----------------------------<br>';}
希望这可以帮助您。
英文:
If you had regular array, you could remove "C" from it, but since you are getting data implicitly from file, this is the solution. Not the most elegant, but works:
// add flag for found value$found = false;foreach(file('num.txt') as $num) {foreach(file('char.txt') as $char) {// condition to show an entryif(!$found || $char != "C") {echo $char.$num. "<br>";if($char == "C" && $num == 3) {echo 'Found it<br>';// you do not need 'break', remove it and set flag instead$found = true;}}}echo '----------------------------<br>';}
答案2
得分: 0
I think your code will be like this:
foreach(file('num.txt') as $num) {foreach(file('char.txt') as $char) {if($char == "C" && $num == 3) {echo 'Found it<br>';break;} else {echo $char . $num . "<br>";}}echo '----------------------------<br>';}
英文:
I think your code will be like this:
foreach(file('num.txt') as $num) {foreach(file('char.txt') as $char) {if($char=="C"&&$num==3){echo 'Found it<br>';break;}else{echo $char.$num. "<br>";}}echo '----------------------------<br>';}
答案3
得分: 0
希望这有所帮助。
<?php$arr1 = ['A','B','C','D'];$arr2 = [1,2,3,4,5];for($i = 0; $i < count($arr1); $i++) {for($j = 0; $j < count($arr2); $j++){if($arr1[$i] == "C" && $arr2[$j] == 3){echo "找到了<br/>";break;}echo $arr1[$i]."".$arr2[$j]."<br/>";}echo "----------------------<br/>";}?>
英文:
Hope this help.
<?php$arr1 = ['A','B','C','D'];$arr2 = [1,2,3,4,5];for($i = 0; $i < count($arr1); $i++) {for($j = 0; $j < count($arr2); $j++){if($arr1[$i] == "C" && $arr2[$j] == 3){echo "Found It<br/>";break;}echo $arr1[$i]."".$arr2[$j]."<br/>";}echo "----------------------<br/>";}?>
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