问题

我在我的代码中遇到了一个错误。当我运行这段代码并定义`"email"`时，Pycharm会显示错误。

```py
ValueError: 无效的字面值以基数10：'mymail'

email = str(input("定义您的电子邮件地址。"))
key_password = int(input("定义您的密码。"))

login = int(input("输入您的电子邮件地址。"))
enter_password = int(input("输入您的密码。"))

if email == login and  key_password == enter_password:
    print("欢迎访问您的会员空间。")
elif email == login and  key_password != enter_password:
    print("密码错误。")
elif email != login and  key_password == enter_password:
    print("电子邮件地址错误。")
else:
    print("电子邮件地址和密码均错误。")

<details>
<summary>英文:</summary>

I have an error with my code. When I run this code and I define `&quot;email&quot;`, Pycharm indicates an error.

```py
ValueError: invalid literal for int() with base 10: &#39;mymail&#39;

email = str(input("Define your email adress. "))
key_password = int(input("Define your password. "))

login = int(input("Input your email adress. "))
enter_password = int(input("Input your password. "))

if email == login and  key_password == enter_password:
    print("Welcome to your member space.")
elif email == login and  key_password != enter_password:
    print("Wrong password.")
elif email != login and  key_password == enter_password:
    print("Wrong email adress.")
else:
    print("Wrong email adress and password.")

答案1

得分: 1

I'm guessing your error comes from here:

login = int(input("Input your email address. "))

You're trying to interpret your input as an int when it will probably be an email address. Maybe you meant to do the following?

login = str(input("Input your email address. "))

As the comments indicated the str() here is redundant since input() returns a string. So you could just do:

login = input("Input your email address. ")

login = int(input("Input your email adress. "))

login = str(input("Input your email adress. "))

login = input("Input your email adress. ")