英文:
Assign Mapped Object to Expression Result in LINQ to Entities
问题
我有以下的子对象,我们使用一个表达式来将我们的 'entity' 映射到我们的 'domain' 模型。当专门调用我们的 ChildRecordService 方法 GetChild 或 GetChildren 时,我们使用这个:
public static Expression<Func<global::Database.Models.ChildRecord, ChildRecord>> MapChildRecordToCommon = entity => new ChildRecord
{
DateTime = entity.DateTime,
Type = entity.Type,
};
public static async Task<List<ChildRecord>> ToCommonListAsync(this IQueryable<global::Database.Models.ChildRecord> childRecords)
{
var items = await
childRecords.Select(MapChildRecordToCommon).ToListAsync().EscapeContext();
return items;
}
public async Task<List<ChildRecord>> GetChildRecords()
{
using (var uow = this.UnitOfWorkFactory.CreateReadOnly())
{
var childRecords = await uow.GetRepository<IChildRecordRepository>().GetChildRecords().ToCommonListAsync().EscapeContext();
return childRecords;
}
}
所以一切都运作正常。然而,我们还有另一个对象,它是该子对象的父对象,在某些情况下,我们也希望在物化和映射过程中获取该子对象。
换句话说,标准对象如下:
private static Expression<Func<global::Database.Models.Plot, Plot>> MapPlotToCommonBasic = (entity) => new Plot
{
Id = entity.Id,
Direction = entity.Direction,
Utc = entity.Utc,
Velocity = entity.Velocity,
};
然而,我还想映射 Plot.ChildRecord 属性,使用我已经创建的 MapChildRecordToCommon 表达式。我创建了第二个表达式来测试这个:
private static Expression<Func<global::Database.Models.Plot, Plot>> MapPlotToCommonAdvanced = (entity) => new Plot
{
ChildRecord = MapChildRecordToCommon.Compile()(entity.ChildRecord)
};
这会失败:
System.NotSupportedException
The LINQ expression node type 'Invoke' is not supported in LINQ to Entities.
是否有一种方法可以重用我现有的 ChildRecord 表达式,将 ChildRecord 对象(即一对一/单个对象)物化到 Plot 对象上?我认为我的问题是由于只有一个对象,无法使用 .Select(Map) 方法。我对表达式不太了解,对此感到困扰。
供参考,实际上在 "Plot" 对象上还有多达 5 或 6 个其他子对象,我也希望为它们创建表达式。
英文:
I have the following child object that we use an expression to map our 'entity' to our 'domain' model. We use this when specifically calling our ChildRecordService method GetChild or GetChildren:
public static Expression<Func<global::Database.Models.ChildRecord, ChildRecord>> MapChildRecordToCommon = entity => new ChildRecord
{
DateTime = entity.DateTime,
Type = entity.Type,
};
public static async Task<List<ChildRecord>> ToCommonListAsync(this IQueryable<global::Database.Models.ChildRecord> childRecords)
{
var items = await
childRecords.Select(MapChildRecordToCommon).ToListAsync().EscapeContext();
return items;
}
public async Task<List<ChildRecord>> GetChildRecords()
{
using (var uow = this.UnitOfWorkFactory.CreateReadOnly())
{
var childRecords= await uow.GetRepository<IChildRecordRepository>().GetChildRecords().ToCommonListAsync().EscapeContext();
return childRecords;
}
}
So that all works just fine. However we have another object that is a parent to that child, that in SOME cases, we also wish to get the child during the materialisation and mapping process.
In other words the standard object looks as such:
private static Expression<Func<global::Database.Models.Plot, Plot>> MapPlotToCommonBasic = (entity) => new Plot
{
Id = entity.Id,
Direction = entity.Direction,
Utc = entity.Utc,
Velocity = entity.Velocity,
};
However what I also want to map is the Plot.ChildRecord property, using the expression MapChildRecordToCommon I have already created. I made a second expression just to test this:
private static Expression<Func<global::Database.Models.Plot, Plot>> MapPlotToCommonAdvanced = (entity) => new Plot
{
ChildRecord = MapChildRecordToCommon.Compile() (entity.ChildRecord)
};
This fails:
System.NotSupportedException
The LINQ expression node type 'Invoke' is not supported in LINQ to Entities.
Is there a way to reuse my existing expression for ChildRecord, to materialise the object of ChildRecord (ie. one to one/singular not multiple) on the Plot object? I think my trouble is caused by there being just one object and being unable to use the .Select(Map) method. I am not too great at expressions and have hit a wall with this.
For reference, there are actually up to 5 or 6 other child objects on the "Plot" object that I also want to make expressions for.
答案1
得分: 0
I resolved this by using the third party library LinqKit.
The library allowed the use of 2 methods, .AsExpandable() (which allows for the expressions to properly compile and be invoked as I understand), and .Invoke() as an extension method to an expression, rather than calling Expression.Invoke(yourexpression). I included a null check just in case.
My code now looks as follows:
public static async Task<List<Plot>> ToCommonListAsync(this IQueryable<global::Database.Models.Plot> plots)
{
var items = await
plots.AsExpandable().Select(MapPlotToCommon).ToListAsync().EscapeContext();
return items;
}
private static Expression<Func<global::Database.Models.Plot, Plot>> MapPlotToCommon = (entity) => new Plot
{
Id = entity.Id,
Direction = entity.Direction,
Utc = entity.Utc,
Velocity = entity.Velocity,
ChildRecord = entity.ChildRecord != null ? MapChildRecordToCommon.Invoke(entity.ChildRecord) : default
};
public static Expression<Func<global::Database.Models.ChildRecord, ChildRecord>> MapChildRecordToCommon = entity => new ChildRecord
{
DateTime = entity.DateTime,
Type = entity.Type,
};
英文:
I resolved this by using the third party library LinqKit.
The library allowed the use of 2 methods, .AsExpandable() (which allows for the expressions to properly compile and be invoked as I understand), and .Invoke() as an extension method to an expression, rather than calling Expression.Invoke(yourexpression). I included a null check just in case.
My code now looks as follows:
public static async Task<List<Plot>> ToCommonListAsync(this IQueryable<global::Database.Models.Plot> plots)
{
var items = await
plots.AsExpandable().Select(MapPlotToCommon).ToListAsync().EscapeContext();
return items;
}
private static Expression<Func<global::Database.Models.Plot, Plot>> MapPlotToCommon = (entity) => new Plot
{
Id = entity.Id,
Direction = entity.Direction,
Utc = entity.Utc,
Velocity = entity.Velocity,
ChildRecord = entity.ChildRecord != null ? MapChildRecordToCommon.Invoke(entity.ChildRecord) : default
};
public static Expression<Func<global::Database.Models.ChildRecord, ChildRecord>> MapChildRecordToCommon = entity => new ChildRecord
{
DateTime = entity.DateTime,
Type = entity.Type,
};
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