How to recover symbols from utf-8

Encoding in Python 2.7 is very hard to understand. Can someone explain to me how get these string's symbols?

Here is my unicode string:

my_str = u'MFADCINEMve000301119 FACTURE EFAD CIN\u2019troD+000000035165 EUR FACTURE EFAD CIN\u2019trop\xe9MA SAS 2019/10198'

And I want to convert it to get "\u2019" and "\xe9".

I already try to my_str.encode('utf-8') but this gives me that:

'MFADCINEMve000301119 FACTURE EFAD CIN\xe2\x80\x99troD+000000035165 EUR FACTURE EFAD CIN\xe2\x80\x99trop\xc3\xa9MA SAS 2019/10198'

with other encoded symbols. I don't understand that, I juste want to replace them into ' and é symbols...

UPDATE:

UPDATE 2:

Here is my code:

day = datetime.now().day
        month = datetime.now().strftime("%b")
        year = datetime.now().strftime("%Y")
        filename = "ventes{0}{1}{2}.csv".format(day, month, year)

        with io.open(filename, 'w', encoding='utf-8') as file_data:
            csvwriter = csv.writer(file_data, delimiter=',', quotechar="", quoting=csv.QUOTE_NONE)

            for line in res:
                csvwriter.writerow([x for x in line])  # Occurs error bellow

        file_data.seek(0)

        out = base64.encodestring(file_data.read())

That occurs this error (not necessarily explicit):

Traceback (most recent call last):
  File "/usr/lib/python2.7/dist-packages/openerp/http.py", line 546, in _handle_exception
    return super(JsonRequest, self)._handle_exception(exception)
  File "/usr/lib/python2.7/dist-packages/openerp/http.py", line 583, in dispatch
    result = self._call_function(**self.params)
  File "/usr/lib/python2.7/dist-packages/openerp/http.py", line 319, in _call_function
    return checked_call(self.db, *args, **kwargs)
  File "/usr/lib/python2.7/dist-packages/openerp/service/model.py", line 118, in wrapper
    return f(dbname, *args, **kwargs)
  File "/usr/lib/python2.7/dist-packages/openerp/http.py", line 316, in checked_call
    return self.endpoint(*a, **kw)
  File "/usr/lib/python2.7/dist-packages/openerp/http.py", line 812, in __call__
    return self.method(*args, **kw)
  File "/usr/lib/python2.7/dist-packages/openerp/http.py", line 412, in response_wrap
    response = f(*args, **kw)
  File "/usr/lib/python2.7/dist-packages/openerp/addons/web/controllers/main.py", line 953, in call_button
    action = self._call_kw(model, method, args, {})
  File "/usr/lib/python2.7/dist-packages/openerp/addons/web/controllers/main.py", line 941, in _call_kw
    return getattr(request.registry.get(model), method)(request.cr, request.uid, *args, **kwargs)
  File "/usr/lib/python2.7/dist-packages/openerp/api.py", line 268, in wrapper
    return old_api(self, *args, **kwargs)
  File "/usr/lib/python2.7/dist-packages/openerp/api.py", line 399, in old_api
    result = method(recs, *args, **kwargs)
  File "/usr/lib/python2.7/dist-packages/openerp/addons_eggs/adquat_export_CEGID/models/export_cegid.py", line 31, in validate
    move_ids = self._context.get('active_ids', [])
UnicodeEncodeError: 'ascii' codec can't encode character u'\xe9' in position 136: ordinal not in range(128)

What's wrong with this code? Please help !

Python 2 by default displays string representations (repr()) as ASCII-only. Any character outside the ASCII range (0-127) is displayed as an escape code (\xnn or \unnnn). The character is only displayed correctly visually if you print the character, and then only if the terminal encoding and font support the character.

For example:

>>> s = u'\xe9'
>>> s             # This is a representation of the string useful for debugging.
u'\xe9'
>>> len(s)        # It is still only length 1.
1
>>> print(s)      # It displays correctly when printed.
é

My terminal's encoding doesn't support all Unicode characters by default, so you're other example doesn't print. The debug representation does, however:

>>> s = u'\u2019'
>>> s
u'\u2019'
>>> len(s)
1
>>> print(s)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "D:\dev\Python27\lib\encodings\cp437.py", line 12, in encode
    return codecs.charmap_encode(input,errors,encoding_map)
UnicodeEncodeError: 'charmap' codec can't encode character u'\u2019' in position 0: character maps to <undefined>

If you write a Unicode string to a file, you have to encode it. Open a file with the encoding you want and write the Unicode string. It's best to use UTF-8 as the encoding, as it supports all Unicode characters. Use io.open. It is compatible with Python 3 (which you should switch to ASAP) and supports the encoding parameter.

import io

my_str = u'MFADCINEMve000301119 FACTURE EFAD CIN\u2019troD+000000035165 EUR FACTURE EFAD CIN\u2019trop\xe9MA SAS 2019/10198'
with io.open('out.txt','w',encoding='utf8') as f:
    f.write(my_str)

Note you have to view the file in an editor that supports UTF-8. For example, on my terminal with its default cp437 encoding it looks like:

C:\>type out.txt
MFADCINEMve000301119 FACTURE EFAD CIN’troD+000000035165 EUR FACTURE EFAD CIN’tropéMA SAS 2019/10198

But if I change the encoding to cp65001 (UTF-8):

C:\>chcp 65001
Active code page: 65001

C:\>type out.txt
MFADCINEMve000301119 FACTURE EFAD CIN’troD+000000035165 EUR FACTURE EFAD CIN’tropéMA SAS 2019/10198

More reading:

• The Absolute Minimum Every Software Developer Absolutely, Positively Must Know About Unicode and Character Sets (No Excuses!)
• Pragmatic Unicode

You just need to do print(my_str.encode('utf-8'))

This will give you the output:

> MFADCINEMve000301119 FACTURE EFAD CIN’troD+000000035165 EUR FACTURE EFAD CIN’tropéMA SAS 2019/10198