英文:
Plot convex-hull in 3D using plotly
问题
我正在尝试使用plotly来绘制一组点的三维凸包。我使用了Mesh3d对象，但表面没有正确创建（请参见下面的图片）。我该如何修复这个问题？
import plotly.graph_objects as goimport itertools, math, numpy as npfrom scipy.spatial import ConvexHull# This simply creates a set of points:n = 3m = 3E = np.array(list(itertools.product(np.arange(-1, 1.1, .5), repeat=m)))V = [[-2.20676418, 1.53670924, -1.5541674 ],[ 0.63437404, 0.07306301, 3.82253086],[ 3.19989112, 0.71987311, 2.79373418]]x = np.array([np.dot(V, e) for e in E])# Then I compute the convex hull using scipy:xc = x[ConvexHull(x).vertices]fig = go.Figure()fig.add_trace(go.Mesh3d(x=xc[:, 0], y=xc[:, 1], z=xc[:, 2], color="blue", opacity=.5))fig
当前输出是:
英文:
I am trying to use plotly to plot the 3D convex-hull of a set of points. I am using Mesh3d objects but the surfaces are not created correctly (see the picture below). How can I fix this?
import plotly.graph_objects as goimport itertools, math, numpy as npfrom scipy.spatial import ConvexHull# This simply creates a set of points:n = 3m = 3E = np.array(list(itertools.product(np.arange(-1, 1.1, .5), repeat=m)))V = [[-2.20676418, 1.53670924, -1.5541674 ],[ 0.63437404, 0.07306301, 3.82253086],[ 3.19989112, 0.71987311, 2.79373418]]x = np.array([np.dot(V, e) for e in E])# Then I compute the convex hull using scipy:xc = x[ConvexHull(x).vertices]fig = go.Figure()fig.add_trace(go.Mesh3d(x=xc[:, 0], y=xc[:, 1], z=xc[:, 2], color="blue", opacity=.5))fig
Current output is:
答案1
得分: 2
I think what you miss is the alphahull option.
If you want a convex hull you need to add alphahull=0:
import plotly.graph_objects as goimport itertools, math, numpy as npfrom scipy.spatial import ConvexHull# This simply creates a set of points:n = 3m = 3E = np.array(list(itertools.product(np.arange(-1, 1.1, .5), repeat=m)))V = [[-2.20676418, 1.53670924, -1.5541674 ],[ 0.63437404, 0.07306301, 3.82253086],[ 3.19989112, 0.71987311, 2.79373418]]x = np.array([np.dot(V, e) for e in E])# Then I compute the convex hull using scipy:xc = x[ConvexHull(x).vertices]fig = go.Figure()fig.add_trace(go.Mesh3d(x=xc[:, 0],y=xc[:, 1],z=xc[:, 2],color="blue",opacity=.5,alphahull=0))fig
将给你想要的立方体：
<details><summary>英文:</summary>I think what you miss is the [alphahull](https://plotly.com/python/reference/#mesh3d-alphahull) option.If you want a convex hull you need to add `alphahull=0`:
import plotly.graph_objects as go
import itertools, math, numpy as np
from scipy.spatial import ConvexHull
This simply creates a set of points:
n = 3
m = 3
E = np.array(list(itertools.product(np.arange(-1, 1.1, .5), repeat=m)))
V = [
[-2.20676418, 1.53670924, -1.5541674 ],
[ 0.63437404, 0.07306301, 3.82253086],
[ 3.19989112, 0.71987311, 2.79373418]
]
x = np.array([np.dot(V, e) for e in E])
Then I compute the convex hull using scipy:
xc = x[ConvexHull(x).vertices]
fig = go.Figure()
fig.add_trace(go.Mesh3d(x=xc[:, 0],
y=xc[:, 1],
z=xc[:, 2],
color="blue",
opacity=.5,
alphahull=0))
fig
will give you the vube you want:![resutl][1][1]: https://i.stack.imgur.com/WuizR.png</details>
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