replace \n from a list in a data frame

I have:

df=pd.DataFrame({'text':[['\nThere are a lot of\n things that \nare worthy','\nS\nU\nP\nE\nR'],['\nAnd there is \nlots to see']]})
df
0	[\nThere are a lot of\n things that \nare wort...
1	[\nAnd there is \nlots to see]

I want to replace all \n's, and keep the same structure.

I tried:

df['new']=df.text.str.replace('\n','')
	text	new
0	[\nThere are a lot of\n things that \nare wort...	NaN
1	[\nAnd there is \nlots to see]	NaN

Any suggestions

You can do:

import re
df['new'] = df['text'].apply(lambda x: [re.sub(r'\n', '', y) for y in x])

First, you can try is to use another escape character to be sure that is fetched as string.

df['new']=df.text.str.replace('\\n','')

Second case, i would suggest to use the method explained in this answer with the "re" library

https://stackoverflow.com/questions/23996118/replace-special-characters-in-a-string-python