英文:
How To Remove an Element from a List Using Another List's Placeholder in Python
问题
I need to remove a certain element from a list of dictionaries. Unfortunately, the only reference to the object needing removal is a place in another list:
enemy_list[num]
I need to take out enemy_list[num] from everyone.
ii = 0
for i in enemy_list:
print(ii, ':', enemy_list[ii])
ii += 1
num = input("Which of your opponents would you like to eliminate? ")
num = int(num)
del everyone[enemy_list[num]]
I cannot remove it from only enemy_list because it is reset multiple times as everyone in list everyone takes a turn.
我尝试过这个问题，但它只适用于从彼此中删除整个列表。有没有办法我可以改变它以适应这种情况？
感谢您的时间！
英文:
I need to remove a certain element from a list of dictionaries. Unfortunately, the only reference to the object needing removal is a place in another list:
enemy_list[num]
I need to take out enemy_list[num] from everyone.
ii = 0
for i in enemy_list:
print(ii, ':', enemy_list[ii])
ii += 1
num = input("Which of your opponents would you like to eliminate? ")
num = int(num)
del everyone[enemy_list[num]]
I cannot remove it from only enemy_list because it is reset multiple times as everyone in list everyone takes a turn.
I tried this question, but it only worked from removing entire lists from eachother. Is there a way I could change it to work for this case?
Thanks for your time!
答案1
得分: 0
everyone.remove(enemy_list[num])
英文:
everyone.remove(enemy_list[num])
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