将一个函数作为参数传递给一个类内部

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英文:

Passing a function as a parameter within a class

问题

在处理传递 processor 函数到响应参数时遇到了问题,这里有一种解决方法,可以参考以下代码:

void CServer::handleGPS(AsyncWebServerRequest *request)
{
    request->send(SPIFFS, "/gps.htm", String(), false, [this](const String &var) { return processor(var); });
}

通过使用 lambda 表达式,你可以将 processor 函数传递给 request->send,并且正确地将参数传递给 processor 函数。

这个 lambda 表达式 [this](const String &var) { return processor(var); } 接受一个参数 var,然后调用你的 processor 函数来处理它。

希望这可以帮助你解决问题。如果有其他问题,请随时提问。

英文:

So I'm trying to enlist the use of ESPAsyncWebServer for a project, and due to the size of said project I'm refactoring my code into a bunch of different libraries. This is to be part of the Client Server handling section.

I've determined how to effectively pass the *request to separate functions for the purpose of cleaning my code up. I.E.
Within my Libraries .cpp file

server->on("/heap", HTTP_GET, [this](AsyncWebServerRequest *request) { handleHeap(request); });

which fires:

void CServer::handleHeap(AsyncWebServerRequest *request) { request->send(200, "text/plain", String(ESP.getFreeHeap())); }

Where I'm running into an issue is trying to pass in my "Processor" function to the response for templating.

String CServer::processor(const String &var)
{
if (var == "locationLat")
return String(gps.location.lat());
return String();
}

void CServer::handleGPS(AsyncWebServerRequest *request)
{
request->send(SPIFFS, "/gps.htm", String(), processor);
}

> error: no matching function for call to
> 'AsyncWebServerRequest::send(fs::FS&, const char [9], String, )

Trying to pass processor() in a Lambda also doesn't compile, because there isn't a parameter going in.

> error: no matching function for call
> to 'CServer::processor()' request->send(SPIFFS, "/gps.htm", String(), [this] { processor(); });
> ^ lib\CServer\CServer.cpp:128:66: note:
> candidate is: lib\CServer\CServer.cpp:108:8: note: String
> CServer::processor(const String&)

sooo, how do I handle passing the required processor function, into my response parameters as instructed in the guide here?

For reference:

String processor(const String& var)
{
if(var == "HELLO_FROM_TEMPLATE")
return F("Hello world!");
return String();
}

// ...

//Send index.htm with template processor function
request->send(SPIFFS, "/index.htm", String(), false, processor);

Fine if its all in main.cpp, but that is not what I want to do!

答案1

得分: 8

由于您的处理器函数是一个类方法,您需要将其与隐式的 this 参数绑定。

我们可以找到回调类型定义:typedef std::function<String(const String&)> AwsTemplateProcessor;

在这里,lambda 表达式以 const String &var 作为参数,就像 AwsTemplateProcessor 一样,并且我们通过在 lambda 原型之后写 -> String 来明确指定 AwsTemplateProcessor 函数的返回类型。通过正确指定参数和返回类型,send 方法可以将 lambda 与 std::functionAwsTemplateProcessor)关联起来。

英文:

Since your processor function is a class method, you'll need to bind it with the implicit this argument.

We can find the callback typedef : typedef std::function&lt;String(const String&amp;)&gt; AwsTemplateProcessor;

request-&gt;send(SPIFFS, &quot;/index.htm&quot;, String(), false, [this](const String &amp;var) -&gt; String { return this-&gt;processor(var); });

The lambda here is taking a const String &amp;var as parameter such as the AwsTemplateProcessor, and we precise the return type of the AwsTemplateProcessor function by writing -&gt; String after the lambda prototype. By precising the parameters and the return type correctly the send method can relate the lambda to the std::function (AwsTemplateProcessor).

答案2

得分: 1

将您的方法设为static,或者调用应该是:

static void CServer::handleGPS(AsyncWebServerRequest *request)
{
    request->send(SPIFFS, "/gps.htm", String(), [this](const String& var) { return processor(var); });
}
英文:

Make your method static, or call should be:

void CServer::handleGPS(AsyncWebServerRequest *request)
{
    request-&gt;send(SPIFFS, &quot;/gps.htm&quot;, String(), [this](const String&amp; var) { return processor(var); });
}

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  • 本文由 发表于 2020年1月3日 16:30:29
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