Add query string url in Go

huangapple
go评论135阅读模式
英文:

Add query string url in Go

问题

我需要将HTTP请求发送到https://some-domain.com/getsomething/?id=myID。我有URL并且需要向其添加查询参数。以下是我的Go代码：

  1. baseUrl := "https://some-domain.com"
  2. relativeUrl := "/getsomething/"
  3. url, _ := url.Parse(baseUrl)
  4. url.Path = path.Join(url.Path, relativeUrl)
  6. // 添加参数到查询字符串
  7. queryString := url.Query()
  8. queryString.Set("id", "1")
  9. // 将查询字符串添加到URL
  10. url.RawQuery = queryString.Encode()
  11. // 打印URL
  12. fmt.Println(url.String())

输出结果是这个URL：https://some-domain.com/getsomething?id=1

而我需要的是这个URL：https://some-domain.com/getsomething/?id=1

你可以看到在?之前没有/字符。

你知道如何在不进行手动字符串操作的情况下修复它吗？

https://play.golang.org/p/HsiTzHcvlQ

英文:

I need to send http request to https://some-domain.com/getsomething/?id=myID
I have url and need to add to it a query parameter. Here is my Go code

  1. baseUrl := "https://some-domain.com"
  2. relativeUrl := "/getsomething/"
  3. url, _ := url.Parse(baseUrl)
  4. url.Path = path.Join(url.Path, relativeUrl)
  6. // add parameter to query string
  7. queryString := url.Query()
  8. queryString.Set("id", "1")
  9. // add query to url
  10. url.RawQuery = queryString.Encode()
  11. // print it 
  12. fmt.Println(url.String())

In output I see this url: https://some-domain.com/getsomething?id=1

And this one is required: https://some-domain.com/getsomething/?id=1

You can see that there is no / character before ?.

Do you know how to fix it without manual string manipulations?

https://play.golang.org/p/HsiTzHcvlQ

答案1

得分: 10

你可以使用ResolveReference方法。

  1. package main
  3. import (
  4. 	"fmt"
  5. 	"log"
  6. 	"net/url"
  7. )
  9. func main() {
  10. 	relativeUrl := "/getsomething/"
  11. 	u, err := url.Parse(relativeUrl)
  12. 	if err != nil {
  13. 		log.Fatal(err)
  14. 	}
  16. 	queryString := u.Query()
  17. 	queryString.Set("id", "1")
  18. 	u.RawQuery = queryString.Encode()
  20. 	baseUrl := "https://some-domain.com"
  21. 	base, err := url.Parse(baseUrl)
  22. 	if err != nil {
  23. 		log.Fatal(err)
  24. 	}
  26. 	fmt.Println(base.ResolveReference(u))
  27. }
英文:

You can use ResolveReference.

  1. package main
  3. import (
  4. 	"fmt"
  5. 	"log"
  6. 	"net/url"
  7. )
  9. func main() {
  10. 	relativeUrl := "/getsomething/"
  11. 	u, err := url.Parse(relativeUrl)
  12. 	if err != nil {
  13. 		log.Fatal(err)
  14. 	}
  16. 	queryString := u.Query()
  17. 	queryString.Set("id", "1")
  18. 	u.RawQuery = queryString.Encode()
  20. 	baseUrl := "https://some-domain.com"
  21. 	base, err := url.Parse(baseUrl)
  22. 	if err != nil {
  23. 		log.Fatal(err)
  24. 	}
  26. 	fmt.Println(base.ResolveReference(u))
  27. }

https://play.golang.org/p/BIU29R_XBM

huangapple
  • 本文由 发表于 2017年9月13日 18:43:34
  • 转载请务必保留本文链接：https://go.coder-hub.com/46195423.html
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