英文:
Regex match cellphone number from string
问题
我想从字符串中匹配正确的电话号码。例如：
string := "my phone number is 15817452367"
re := regexp.MustCompile(`1[34578][0-9]{9}`)
re.FindAllString(string, -1)
-> 15817452367
这个结果是正确的，但对于另一个字符串：
string := "my card number is 115817452367"
re := regexp.MustCompile(`1[34578][0-9]{9}`)
re.FindAllString(string, -1)
-> 15817452367 (无效)
这个正则表达式也匹配了电话号码，但我不希望从数字字符串中获取电话号码。我该如何修复这个正则表达式？提前感谢！
英文:
I want to match the right phone number from a string. For example:
string := "my phone number is 15817452367"
re := regexp.MustCompile(`1[34578][0-9]{9}`)
re.FindAllString(string, -1)
-> 15817452367
This result is right, but for another string:
string := "my card number is 115817452367"
re := regexp.MustCompile(`1[34578][0-9]{9}`)
re.FindAllString(string, -1)
-> 15817452367 (invalid)
This regex also matches the phone number, but I want this to not be a valid value，I don't want to get a phone number form a digital string. How can I fix the regex? Thanks in advance!
答案1
得分: 3
你可以检查正则表达式的开头和结尾，以确定字符串的开头/结尾或非数字字符，并且只捕获电话号码。
以下是一个工作正则表达式的示例：
(?:^|[^0-9])(1[34578][0-9]{9})(?:$|[^0-9])
在 Golang 中的使用示例：
re := regexp.MustCompile(`(?:^|[^0-9])(1[34578][0-9]{9})(?:$|[^0-9])`)
submatch := re.FindStringSubmatch("Phone Number: 15817452367;")
if len(submatch) < 2 {
// 未找到匹配项
}
match := submatch[1]
解释：
找到字符串的开头或非数字字符，放在非捕获组中：
(?:^|[^0-9])
找到要搜索的电话号码，放在捕获组中：
(1[34578][0-9]{9})
找到字符串的结尾或非数字字符，放在非捕获组中：
(?:$|[^0-9])
英文:
You can check the beginning and end of the regex for the beginning/end of the string or a non-digit character and only capture the phone number.
Here is some working Regex as an example:
(?:^|[^0-9])(1[34578][0-9]{9})(?:$|[^0-9])
In Golang
re := regexp.MustCompile(`(?:^|[^0-9])(1[34578][0-9]{9})(?:$|[^0-9])`)
submatch := re.FindStringSubmatch("Phone Number: 15817452367;")
if len(submatch) < 2 {
// No match found
}
match := submatch[1]
Explanation:
Find the start of the string or a non-digit character.
Enclosed in non-capture group.
(?:^|[^0-9])
Find the phone number you are searching for.
Enclosed in capture group.
(1[34578][0-9]{9})
Find the end of the string or a non-digit character.
Enclosed in non-capture group.
(?:$|[^0-9])
答案2
得分: 0
你可以检查匹配的字符串前后是否没有数字。
为了检查这一点，将你的模式嵌套在两个[^0-9]*之间：它表示“没有或不是数字”。
regexp.MustCompile(`[^0-9]*1[34578][0-9]{9}[^0-9]*`)
这样，15817452367将被检测为匹配，但115817452367将不会。
英文:
You can check if the matched string is not preceded nor followed by digits.
In order to check this, nest your pattern between two [^0-9]*: it means "nothing or not a digit".
regexp.MustCompile(`[^0-9]*1[34578][0-9]{9}[^0-9]*`)
This way, 15817452367 will be detected as a match, but 115817452367 will not.
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