英文:
golang download file and follow redirects
问题
你想要从重定向的URL下载文件，并将文件名返回到变量filename中。你的实际代码如下：
package mainimport ("os""net/http""io""path/filepath")func downloadFile(filepath string, url string) (string, error) {// Create the fileout, err := os.Create(filepath)if err != nil {return "", err}defer out.Close()// Get the dataresp, err := http.Get(url)if err != nil {return "", err}defer resp.Body.Close()// Writer the body to file_, err = io.Copy(out, resp.Body)if err != nil {return "", err}// Get the real filenamerealFilename := filepath.Base(resp.Request.URL.Path)return realFilename, nil}func main() {var filename string = "urls.txt"var url1 string = "http://94.177.247.162:5000/random"realFilename, err := downloadFile(filename, url1)if err != nil {panic(err)}// Use the real filenamefilename = realFilename// Print the filenameprintln(filename)}
你可以通过在downloadFile函数中添加一些代码来获取实际的文件名。使用filepath.Base(resp.Request.URL.Path)可以从URL的路径中提取文件名。然后，你可以将实际的文件名赋值给filename变量，并打印出来。
英文:
i want to download file from redirect url, and return filename in variable filename, my actual code is :
package mainimport ("os""net/http""io")func downloadFile(filepath string, url string) (err error) {// Create the fileout, err := os.Create(filepath)if err != nil {return err}defer out.Close()// Get the dataresp, err := http.Get(url)if err != nil {return err}defer resp.Body.Close()// Writer the body to file_, err = io.Copy(out, resp.Body)if err != nil {return err}return nil}func main() {var filename string = "urls.txt"var url1 string = "http://94.177.247.162:5000/random"downloadFile(filename, url1)}
how i can change my code to return real name of file downloaded in variable filename.
example output :
urlix.txt
答案1
得分: 2
重定向应该是默认跟随的。你可以使用以下代码获取访问的最终URL来获取下载链接：
finalURL := resp.Request.URL.String()
URL的最后一部分是远程文件的文件名，所以可以使用以下代码来获取文件名：
parts := strings.Split(finalURL, "/")filename := parts[len(parts)-1]
英文:
Redirects should be followed by default. You can get the final url visited to aquire the download using
finalURL := resp.Request.URL.String()
The last part of the url is your filename on the remote so something like this should work
parts := strings.Split(finalURL, "/")
filename := parts[len(parts)-1]
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