英文:
The difference between "A" and "A"[0]
问题
我为将TEXT转换为BINARY编写了以下代码：
fmt.Printf("%s\n", fmt.Sprintf("%08b", "A"))
但是它不起作用，输出的消息是：%!b(string=0000000A)
但是当我将"A"更改为"A"[0]时，它正常工作：
fmt.Printf("%s\n", fmt.Sprintf("%08b", "A"[0]))
输出结果是01000001
上述语句之间有什么区别？
英文:
I write this code for convert TEXT to BINARY
fmt.Printf("%s\n", fmt.Sprintf("%08b", "A"))
and not work, print message: %!b(string=0000000A)
but when i changed "A" to "A"[0] work fine:
fmt.Printf("%s\n", fmt.Sprintf("%08b", "A"[0]))
output is 01000001
what is difference between above statements?
答案1
得分: 4
Golang将字符串与字节区分开来。
"A"是一个字符串，严格来说是一个只读的字节切片。"A"[0]是该序列中的第一个字节，其值为0x41。
你要求先打印一个字符串("A")，然后再打印一个字节("A"[0])，并使用二进制数字在一个长度为八个字符的字段中显示。你的第一个输出很有趣，因为你试图将一个字符串打印成某种字节值。但是，一个字节序列并不等同于一个单独的字节。你的第二个输出更自然，因为你获取了字符串的第一个字节（索引为0），得到了0x41。
英文:
Golang differentiates strings from bytes.
"A" is a string, technically a read-only slice of bytes. "A"[0] is the first byte in this sequence, whose value is 0x41.
You asked to print first a string ("A"), then secondly a byte ("A"[0]), in a field of eight characters using binary digits. Your first output was funny because you tried to print a string as if it were some kind of byte value. But a sequence of one byte is not the same as a single byte. Your second output was more natural, since you grabbed the first byte of the string (at index 0), obtaining 0x41.
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