从字符串或字节数组创建一个XML解码器。

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英文:

Create a XML Decoder from a string or byte array GO

问题

我在我的应用程序中有一个XML解码函数,并且我使用xml.NewDecoder(resp.Body)来解码我的XML。NewDecoder函数接收一个io.Reader。但问题是,在来自服务器的响应中,我收到了前230个字节,我需要忽略,剩下的字节是我想要解码的以base64编码的XML。以下是响应正文的示例:

    --随机字符...
    Content-Type: application/xml; charset=UTF-8; name=response_xml

    <Response success="1"/>
    --随机字符...
    Content-Type: text/xml; name=report.xml
    Content-Transfer-Encoding: base64
    PE5leHBvc2VSZXBvcnQgdmVyc2lvbj0iMi4wIj4KPHNjYW5zPgo8c2NhbiBpZD0iNDYwMCIgbmFt......

我只需要读取PE5leHBvc2VSZXBv...的数据。使用以下代码,我可以读取XML:

    bodyBytes, _ := ioutil.ReadAll(resp.Body)
    defer resp.Body.Close()
    data, err := base64.StdEncoding.DecodeString(string(bodyBytes)[230:])
    fmt.Println(data)

但是,我无法调用xml.NewDecoder()函数,因为data不是io.Reader类型。有没有办法从字符串创建一个Decode对象?

英文:

I have a xml decode function in my app and I use xml.NewDecoder(resp.Body) to decode my xml. the NewDecoder functions receives an io.Reader. But the problem is that in my response from the server I receive the first 230 bytes i need to ignore and the remaining bytes are the xml encoded in base64 that I want to decode. Here an example of the response body:

    --RandomCaracteres...
    Content-Type: application/xml; charset=UTF-8; name=response_xml

    <Response success="1"/>
    --RandomCaracteres...
    Content-Type: text/xml; name=report.xml
    Content-Transfer-Encoding: base64
    PE5leHBvc2VSZXBvcnQgdmVyc2lvbj0iMi4wIj4KPHNjYW5zPgo8c2NhbiBpZD0iNDYwMCIgbmFt......

I need to read only the PE5leHBvc2VSZXBv... data. With the following code I can read the xml:

    bodyBytes, _ := ioutil.ReadAll(resp.Body)
    defer resp.Body.Close()
    data, err := base64.StdEncoding.DecodeString(string(bodyBytes)[230:])
    fmt.Println(data)

but I can't call the xml.NewDecoder() function because data is not a io.Reader type. Is there any way to creade a Decode object from a string?

答案1

得分: 3

是的,有的

r := strings.NewReader(dataStr)

对于字节数组也是一样

r := bytes.NewReader(dataBytes)

或者,使用字节数组,你可以完全跳过ReaderNewDecoder,直接使用Unmarshal

err := xml.Unmarshal(dataBytes, &myobj)

或者使用string,进行类型转换并使用Unmarshal

err := xml.Unmarshal([]byte(dataStr), &myobj)
英文:

Yes there is:

r := strings.NewReader(dataStr)

And likewise for byte arrays:

r := bytes.NewReader(dataBytes)

Or, using bytes, you can skip the Reader and NewDecoder entirely and just use Unmarshal directly:

err := xml.Unmarshal(dataBytes, &myobj)

Or with a string, cast and use Unmarshal:

err := xml.Unmarshal([]byte(dataStr), &myobj)

huangapple
  • 本文由 发表于 2017年9月2日 04:52:31
  • 转载请务必保留本文链接:https://go.coder-hub.com/46007827.html
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