英文:
multiple-value json.Marshal() in single-value context
问题
你可以在这里看到这段代码：
package main
import (
"fmt"
"encoding/json"
)
func main() {
map1 := map[string]map[string]interface{}{}
map2 := map[string]interface{}{}
map2["map2item"] = "map2item"
map1["map2"] = map2
fmt.Println(string(json.Marshal(map1)))
}
它返回以下错误：
tmp/sandbox100532722/main.go:13:33: multiple-value json.Marshal() in single-value context.
我该如何修复这个错误？
英文:
Here you can see this code:
package main
import (
"fmt"
"encoding/json"
)
func main() {
map1 := map[string]map[string]interface{}{}
map2 := map[string]interface{}{}
map2["map2item"] = "map2item"
map1["map2"] = map2
fmt.Println(string(json.Marshal(map1)))
}
that returns this error:
tmp/sandbox100532722/main.go:13:33: multiple-value json.Marshal() in single-value context.
How do I fix this?
答案1
得分: 22
你正在尝试进行的字符串转换需要一个参数，但是json.Marshal函数返回两个值（[]byte和error）。你需要存储第一个返回值，然后进行转换：
package main
import (
"fmt"
"encoding/json"
)
func main() {
map1 := map[string]map[string]interface{}{}
map2 := map[string]interface{}{}
map2["map2item"] = "map2item"
map1["map2"] = map2
b, err := json.Marshal(map1)
if err != nil {
panic(err)
}
fmt.Println(string(b))
}
英文:
The string conversion you are trying to perform requires a single argument, but the json.Marshal function returns two ([]byte and error). You need to store the first return value and then do the conversion:
package main
import (
"fmt"
"encoding/json"
)
func main() {
map1 := map[string]map[string]interface{}{}
map2 := map[string]interface{}{}
map2["map2item"] = "map2item"
map1["map2"] = map2
b, err := json.Marshal(map1)
if err != nil {
panic(err)
}
fmt.Println(string(b))
}
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