英文:
Regex Replace within Sub Match
问题
给定一个字符串（日志文件中的一行）：
Date=2017-06-29 03:10:01.140 -700 PDT,clientDataRate="12.0,18.0,24.0,36.0,48.0,54.0",host=superawesomehost.foo,foo=bar
我想将逗号替换为一个空格，但只在双引号内部替换。
期望的结果：
Date=2017-06-29 03:10:01.140 -700 PDT,clientDataRate="12.0 18.0 24.0 36.0 48.0 54.0",host=superawesomehost.foo,foo=bar
我已经开始使用基本的正则表达式和ReplaceAllString，但很快意识到我不知道如何实现所需的匹配组（？）。
package main
import (
"fmt"
"log"
"regexp"
)
func main() {
logLine := "Date=2017-06-29 03:10:01.140 -700 PDT,clientDataRate=\"12.0,18.0,24.0,36.0,48.0,54.0\",host=superawesomehost.foo,foo=bar"
fmt.Println("logLine: ", logLine)
reg, err := regexp.Compile(`"([^"]*)"`)
if err != nil {
log.Fatal(err)
}
repairedLogLine := reg.ReplaceAllStringFunc(logLine, func(match string) string {
return strings.Replace(match, ",", " ", -1)
})
fmt.Println("repairedLogLine:", repairedLogLine)
}
非常感谢任何帮助。
英文:
Given a string (a line in a log file):
Date=2017-06-29 03:10:01.140 -700 PDT,clientDataRate="12.0,18.0,24.0,36.0,48.0,54.0",host=superawesomehost.foo,foo=bar
I'd like to replace the commas with a single space, but only within double quotes.
Desired result:
Date=2017-06-29 03:10:01.140 -700 PDT,clientDataRate="12.0 18.0 24.0 36.0 48.0 54.0",host=superawesomehost.foo,foo=bar
I've begun with a basic combination of regex and ReplaceAllString but am rapidly realizing I don't understand how to implement the match group (?) needed to accomplish this.
package main
import (
"fmt"
"log"
"regexp"
)
func main() {
logLine := "Date=2017-06-29 03:10:01.140 -700 PDT,clientDataRate=\"12.0,18.0,24.0,36.0,48.0,54.0\",host=superawesomehost.foo,foo=bar"
fmt.Println("logLine: ", logLine)
reg, err := regexp.Compile("[^A-Za-z0-9=\"-:]+")
if err != nil {
log.Fatal(err)
}
repairedLogLine := reg.ReplaceAllString(logLine, ",")
fmt.Println("repairedLogLine:", repairedLogLine )
}
All help is much appreciated.
答案1
得分: 5
你需要使用Regexp.ReplaceAllStringFunc函数，它允许你将函数的结果用作子字符串的替换：
package main
import (
"fmt"
"log"
"regexp"
"strings"
)
func main() {
logLine := `Date=2017-06-29 03:10:01.140 -700 PDT,clientDataRate="12.0,18.0,24.0,36.0,48.0,54.0",host=superawesomehost.foo,foo=bar`
fmt.Println("logLine: ", logLine)
reg, err := regexp.Compile(`"([^"]*)"`)
if err != nil {
log.Fatal(err)
}
repairedLogLine := reg.ReplaceAllStringFunc(logLine, func(entry string) string {
return strings.Replace(entry, ",", " ", -1)
})
fmt.Println("repairedLogLine:", repairedLogLine)
}
https://play.golang.org/p/BsZxcrrvaR
英文:
You'll want to use Regexp.ReplaceAllStringFunc, which allows you to use a function result as the replacement of a substring:
package main
import (
"fmt"
"log"
"regexp"
"strings"
)
func main() {
logLine := `Date=2017-06-29 03:10:01.140 -700 PDT,clientDataRate="12.0,18.0,24.0,36.0,48.0,54.0",host=superawesomehost.foo,foo=bar`
fmt.Println("logLine: ", logLine)
reg, err := regexp.Compile(`"([^"]*)"`)
if err != nil {
log.Fatal(err)
}
repairedLogLine := reg.ReplaceAllStringFunc(logLine, func(entry string) string {
return strings.Replace(entry, ",", " ", -1)
})
fmt.Println("repairedLogLine:", repairedLogLine)
}
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