英文:
Creating a flat array from the map entries in Go
问题
从一个映射中创建一个数组，同时保持时间复杂度较低的最短（且习惯用法）的方法是什么？
例如，从以下映射中：
map[string]string { "1":"a", "2":"b" }
我需要创建以下数组：
[]string{"1","a", "2","b"}
我可以在Scala中使用以下代码实现：
val myMap = Map("1" -> "a", "2" -> "b")
myMap.keySet ++ myMap.values
谢谢。
英文:
What is the shortest (and idiomatic) way to create an array from the keys and values of a map w/o compromising on time complexity too much?
For instance, from the following map:
map[string]string { "1":"a", "2":"b" }
I need to create the following array:
[]string{"1","a", "2","b"}
I can do this in Scala with following:
val myMap = Map("1" -> "a", "2" -> "b")
myMap.keySet ++ myMap.values
Thank you.
答案1
得分: 22
最简单的方法是遍历地图，因为在Go中，语法允许直接访问键和值，并将它们转储到数组中。
m := map[string]string{"1": "a", "2": "b"}
arr := []string{}
for k, v := range m {
arr = append(arr, k, v)
}
这里有一个注意事项：在Go中，地图的迭代顺序是随机的，你可以在这里看到，参考"迭代顺序"：
https://blog.golang.org/go-maps-in-action
因此，如果你希望最终的数组具有特定的顺序，你应该首先转储键和顺序（如同博客中所示）。
Playground（不包含排序部分）：
https://play.golang.org/p/mCe6eEy25A
英文:
Simplest way would be to just iterate the map, since in Go the syntax would allow direct access to keys and values and dump them into the array.
m := map[string]string { "1":"a", "2":"b" }
arr := []string{}
for k, v := range m {
arr = append(arr, k, v)
}
One caveat here: In Go, map iteration order is randomized, as you can see here, under "Iteration Order":
https://blog.golang.org/go-maps-in-action
So if you want your resulting array to have a particular ordering, you should first dump the keys and order (as shown in that same blog entry).
Playground (without the sorting part):
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