http.ServeFile和http.ServeContent无法处理多个客户端。

huangapple go评论101阅读模式
英文:

http.ServeFile and http.ServeContent cannot handle multiple clients

问题

场景:
我使用golang创建了一个简单的视频流媒体服务器。起初,我使用http.ServeContent来提供视频内容。在我同时连接4个选项卡到服务器时,前两个选项卡可以正常工作,但是其他选项卡无法加载。我可以在播放两个视频的同时导航到菜单,但是其他选项卡无法播放视频。我还尝试了在多个设备上进行测试,只有两个连接可以播放视频。

因此,我将http.ServeContent更改为http.ServeFile,但问题仍然存在。当我使用io.Pipes时,它可以处理每个请求,但问题是它无法进行定位。

以下是我的代码:

package main

import (
	"log"
	"net"
	"net/http"

	"github.com/gorilla/mux"
)

func serveVideo(w http.ResponseWriter, r *http.Request) {
	vars := mux.Vars(r)
	title := vars["title"]
	ep := vars["ep"]
	http.ServeFile(w, r, "video/"+title+"/"+ep+".mp4")
}

func main() {
	const port string = "8080"
	// 创建mux路由器
	r := mux.NewRouter()
	r.HandleFunc("/video/{title}/{ep}", serveVideo)
	// 让mux处理
	http.Handle("/", r)
	if err := http.ListenAndServe(":8080", nil); err != nil {
		log.Fatal(err)
	}
}

希望这可以帮到你。谢谢。

英文:

Scenario <br>
I created a simple video streamer using golang. At First, I used http.ServeContent to serve my videos. It was working until I simultaneously connected 4 tabs to my server but the first two only works and the rest aren't loading at all. I can navigate to the menu while streaming the two videos but I can't stream on the rest. I also tried it using multiple devices. Only two connections can stream.

So, I changed http.ServeContent to http.ServeFile but its still the same but when I used io.Pipes, It served every request but the problem is that It can't seek.

Here is my code:

package main

import (
    &quot;log&quot;
    &quot;net&quot;
    &quot;net/http&quot;

    &quot;github.com/gorilla/mux&quot;
)

func serveVideo(w http.ResponseWriter, r *http.Request) {
    vars := mux.Vars(r)
    title := vars[&quot;title&quot;]
    ep := vars[&quot;ep&quot;]
    http.ServeFile(w, r, &quot;video/&quot; + title + &quot;/&quot; ep + &quot;.mp4&quot;)
}

func main() {
     const port string = &quot;8080&quot;
    // Create mux router
    r := mux.NewRouter()
    r.HandleFunc(&quot;/video/{title}/{ep}&quot;, serveVideo)
    // let mux handle
    http.Handle(&quot;/&quot;, r)
    if err := http.ListenAndServe(&quot;:8080&quot;, nil); err != nil {
	    log.Fatal(err)
    }
}

I wish you could help. Thank you.

答案1

得分: 1

我怀疑你的代码没问题。所有主要的浏览器通常会限制与主机的并行活动连接数。

作为一个简单的测试,尝试使用类似于 curl 的工具多次进行流式传输,以确认你的代码是否真的存在问题。或者,尝试同时运行不同的浏览器(例如,在Chrome中打开2个标签,在Firefox中打开2个标签等)。

英文:

I suspect your code is fine. All major browsers will normally limit the number of parallel active connections to a host.

As a simple test, try streaming multiple times with something like curl to confirm there is actually a problem with your code. Alternatively, try running different browsers simultaneously (e.g. 2 tabs in Chrome, 2 tabs in Firefox etc)

huangapple
  • 本文由 发表于 2017年8月8日 02:30:42
  • 转载请务必保留本文链接:https://go.coder-hub.com/45553532.html
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定