从字符串中删除反斜杠。

huangapple
go评论122阅读模式
英文:

Remove backslash from the string

问题

我想将字符串发送到服务器。我的字符串如下所示，

str := "[{"name":"cpu","status":"%d"}, {"name":"LTE","status":"%d"}, {"name":"Network","status":"%d"}, {"name":"Memory","status":"%d"}]"

当我使用"fmt.Println(str)"打印它时，输出如下所示，

[{"name":"cpu","status":"%d"}, {"name":"LTE","status":"%d"}, {"name":"Network","status":"%d"}, {"name":"Memory","status":"%d"}]

但是当我将相同的字符串发送到服务器时，服务器接收到的字符串如下所示，

"[{"name":"cpu","status":"%d"}, {"name":"LTE","status":"%d"}, {"name":"Network","status":"%d"}, {"name":"Memory","status":"%d"}]"

请查看我的代码片段如下：

func (m *MetricSet) Fetch() (common.MapStr, error) {
var x string
x =fmt.Sprintf("[{"name":"cpu","status":"%d"}, {"name":"LTE","status":"%d"}, {"name":"Network","status":"%d"}, {"name":"Memory","status":"%d"}]", 17,26,34,33)
fmt.Println(x)
event := common.MapStr{
"cpu_status": (m.cpu_status%4),
"memory_status" : (m.memory_status%4),
"lte_status" : (m.lte_status%4),
"network_status" : (m.network_status%4),
"summary": x,
}

  1.     m.cpu_status++
  2.     m.memory_status = m.memory_status + 2
  3.     m.lte_status = m.lte_status + 7
  4.     m.network_status = m.network_status + 13
  6.     return event, nil

}

如何解决这个问题？请帮助我。

英文:

I want to send the string to the server.My string is like as below,

  1.   str := "[{\"name\":\"cpu\",\"status\":\"%d\"}, {\"name\":\"LTE\",\"status\":\"%d\"}, {\"name\":\"Network\",\"status\":\"%d\"}, {\"name\":\"Memory\",\"status\":\"%d\"}]"

When I print it using "fmt.Println(str)",it gives desired output as below,

  1. [{"name":"cpu","status":"%d"}, {"name":"LTE","status":"%d"}, {"name":"Network","status":"%d"}, {"name":"Memory","status":"%d"}]

But when I am sending same string to server,server receives string as below,

  1. "[{\"name\":\"cpu\",\"status\":\"%d\"}, {\"name\":\"LTE\",\"status\":\"%d\"}, {\"name\":\"Network\",\"status\":\"%d\"}, {\"name\":\"Memory\",\"status\":\"%d\"}]"

Please find my code snippet as below:

  1. func (m *MetricSet) Fetch() (common.MapStr, error) {
  2.         var x string
  3.         x =fmt.Sprintf("[{\"name\":\"cpu\",\"status\":\"%d\"}, {\"name\":\"LTE\",\"status\":\"%d\"}, {\"name\":\"Network\",\"status\":\"%d\"}, {\"name\":\"Memory\",\"status\":\"%d\"}]", 17,26,34,33)
  4.         fmt.Println(x)
  5.         event := common.MapStr{
  6.                 "cpu_status": (m.cpu_status%4),
  7.                 "memory_status" : (m.memory_status%4),
  8.                 "lte_status" : (m.lte_status%4),
  9.                 "network_status" : (m.network_status%4),
  10.                 "summary": x,
  11.         }
  13.         m.cpu_status++
  14.         m.memory_status = m.memory_status + 2
  15.         m.lte_status = m.lte_status + 7
  16.         m.network_status = m.network_status + 13
  18.         return event, nil
  19. }

How to solve it?Please help me.

答案1

得分: 1

你正在将摘要内容作为字符串发送，而不是作为映射切片发送。

  1. k := [...]common.MapStr{
  2.     {"name": "cpu", "status": m.cpu_status},
  3.     {"name": "LTE", "status": m.lte_status},
  4.     {"name": "Network", "status": m.network_status},
  5.     {"name": "Memory", "status": m.memory_status},
  6. }
  7. event := common.MapStr{
  8.     "cpu_status":     (m.cpu_status % 4),
  9.     "memory_status":  (m.memory_status % 4),
  10.     "lte_status":     (m.lte_status % 4),
  11.     "network_status": (m.network_status % 4),
  12.     "summary":        k,
  13. }

参考链接：https://play.golang.org/p/yTSXnNKclG

英文:

You are sending the content of summary as a string so, instead you need to send it as a slice of maps

  1. k := [...]common.MapStr{
  2. 	{"name": "cpu", "status": m.cpu_status},
  3. 	{"name": "LTE", "status": m.lte_status},
  4. 	{"name": "Network", "status": m.network_status},
  5. 	{"name": "Memory", "status": m.memory_status},
  6. }
  7. event := common.MapStr{
  8. 	"cpu_status":     (m.cpu_status % 4),
  9. 	"memory_status":  (m.memory_status % 4),
  10. 	"lte_status":     (m.lte_status % 4),
  11. 	"network_status": (m.network_status % 4),
  12. 	"summary":        k,
  13. }

See https://play.golang.org/p/yTSXnNKclG

答案2

得分: 1

当event被编组为JSON时，如果summary包含双引号，其值将被转义。一种快速而简单的解决方案是将event定义为map[string]interface{}，以便能够将任意类型存储为映射值，并将summary值存储为json.RawMessage，例如：

  1. event := map[string]interface{}{
  2.     "cpu_status": (m.cpu_status%4),
  3.     "memory_status": (m.memory_status%4),
  4.     "lte_status": (m.lte_status%4),
  5.     "network_status": (m.network_status%4),
  6.     "summary": json.RawMessage(x),
  7. }

但是，您需要确保x的值是有效的JSON对象（这容易出错）。更健壮的解决方案是将summary中的项定义为结构类型，例如：

  1. type Status struct {
  2.     Name string `json:"name"`
  3.     Status string `json:"status"`
  4. }
  5. summary := []*Status{
  6.     &Status{"cpu", "17"},
  7.     &Status{"LTE", "26"},
  8.     &Status{"Network", "34"},
  9.     &Status{"Memory", "33"},
  10. }
  12. event := map[string]interface{}{
  13.     "cpu_status": (m.cpu_status%4),
  14.     "memory_status": (m.memory_status%4),
  15.     "lte_status": (m.lte_status%4),
  16.     "network_status": (m.network_status%4),
  17.     "summary": summary,
  18. }
英文:

When event is marshalled into JSON, the value of summary will be escaped if it contains a double quote. The quick and dirty solution will be defined the event as map[string]interface{} to be able to store arbitrary type as map value, and store the summary value as json.RawMessage e.g.

  1. event := map[string]interface{}{
  2.     "cpu_status": (m.cpu_status%4),
  3.     "memory_status" : (m.memory_status%4),
  4.     "lte_status" : (m.lte_status%4),
  5.     "network_status" : (m.network_status%4),
  6.     "summary": json.RawMessage(x),
  7. }

However, you need to make sure that the value of x is a valid JSON object (which is error prone). More robust solution is by defining the items in summary as a struct type, e.g.

  1. type Status struct {
  2. 	Name string `json:"name"`
  3. 	Status string `json:"status"`
  4. }
  5. summary := []*Status{
  6. 	&Status{"cpu", "17"},
  7. 	&Status{"LTE", "26"},
  8. 	&Status{"Network", "34"},
  9. 	&Status{"Memory", "33"},
  10. }
  12. event := map[string]interface{}{
  13.     "cpu_status": (m.cpu_status%4),
  14.     "memory_status" : (m.memory_status%4),
  15.     "lte_status" : (m.lte_status%4),
  16.     "network_status" : (m.network_status%4),
  17.     "summary": summary,
  18. }

huangapple
  • 本文由 发表于 2017年8月1日 14:10:04
  • 转载请务必保留本文链接：https://go.coder-hub.com/45430126.html
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