英文:
Howto fill variant args from a loop
问题
对于以下示例,我需要从文件中读取值(没有问题),并将其作为数据点放入方法"func (r *Regression) Train(d ...*dataPoint)"中。这样可以实现:
r.Train(
regression.DataPoint(1, []float64{1, 1, 1}),
regression.DataPoint(4, []float64{2, 2, 2}),
regression.DataPoint(9, []float64{3, 3, 3}),
)
但是我想要像这样使用循环来实现:
for i := 1; i <= 4; i++ {
??? regression.DataPoint(i*i, []float64{i, i, i}), ???
}
我不能使用dataPoint的数组,因为它只在该包中可见。这是完整的源代码:
https://github.com/sajari/regression(查看示例用法)
非常感谢,
Maciej
英文:
for the following example I need to read values from a file (no problem) and put it into the method "func (r *Regression) Train(d ...*dataPoint)" as datapoints. This works:
r.Train(
regression.DataPoint(1, []float64{1, 1, 1}),
regression.DataPoint(4, []float64{2, 2, 2}),
regression.DataPoint(9, []float64{3, 3, 3}),
)
but I would like to put it from a loop like this:
for i := 1; i <= 4; i++ {
??? regression.DataPoint(i*i, []float64{i, i, i}), ???
}
I can not use an array of dataPoint as it is only visible in that package. Here is the full source code:
https://github.com/sajari/regression (see example usage)
Thank you very much,
Maciej
答案1
得分: 1
从你提供的链接页面上可以看到:
注意:你也可以逐个添加数据点。
因此,你需要:
for i := 1; i <= 4; i++ {
r.Train(regression.DataPoint(i*i, []float64{i, i, i}))
}
英文:
From the page you linked:
Note: You can also add data points one by one.
Therefore you need:
for i := 1; i <= 4; i++ {
r.Train(regression.DataPoint(i*i, []float64{i, i, i}))
}
答案2
得分: 0
@Milo的答案可能适用于你的特定情况,但对于具有可变参数函数的一般情况,你可以将元素追加到切片中,然后将切片用作可变参数列表:
r.Train(points...)
不幸的是,回归库设计得不太好,因为它公开暴露了接收和返回未公开类型的函数,这样你就无法处理它们。
英文:
@Milo's answer is probably best for your particular case, but for the general case with variadic functions, you can append elements to a slice, then use the slice as the variadic argument list:
r.Train(points...)
Unfortunately the regression library is not very well-designed, as it has publicly-exposed functions that receive and return unexposed types, leaving you no way to work with them.
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