英文:
More readable way of not matching negated words in a sentence
问题
我正在尝试在句子中不匹配否定词，例如带有not、never等的形容词。目前我使用的是字符级别的否定。例如对于not，可以使用正则表达式^(?:[^n]+|n(?:$|[^o]|o(?:$|[^t]|\w)))。是否有更简单（更易读）的方法来处理一个或多个否定词（如not、never、any、nobody等）？以下是关于not否定的代码示例：
package main
import (
"fmt"
"regexp"
)
func main() {
sentence := "he is not satisfied"
re := regexp.MustCompile(`^(?:[^n]+|n(?:$|[^o]|o(?:$|[^t])))\ssatisfied`)
fmt.Println(re.FindAllString(sentence, -1))
sentence = "he is satisfied"
fmt.Println(re.FindAllString(sentence, -1))
}
谢谢。
英文:
I am trying to not match negated word in a sentence such as adjective with not, never for example. Currently I used character level negation. Example for not ^(?:[^n]+|n(?:$|[^o]|o(?:$|[^t]|\w))). Is there an easy way (more readable) of doing this for one or many negation words (not, never, any, nobody, ......). Here is a code for not negation:
package main
import(
"fmt"
"regexp"
)
func main (){
sentence:="he is not satisfied"
re := regexp.MustCompile(`^(?:[^n]+|n(?:$|[^o]|o(?:$|[^t])))\ssatisfied`)
fmt.Println(re.FindAllString(sentence, -1))
sentence="he is satisfied"
fmt.Println(re.FindAllString(sentence, -1))
}
Thanks
答案1
得分: 2
很遗憾，出于性能原因（尽管Go的正则表达式解析器本身并不特别高效），Go的正则表达式包不支持前瞻/后顾，因此没有很好的方法可以使用正则表达式来实现这个功能。
无论如何，正则表达式并不是很适合这种情况。它需要一个非常复杂的表达式来完成一个非常简单的匹配。如果我要实现类似的功能，我可能会将字符串按空格/标点符号分割，并进行自己的匹配。这样更容易处理，而且可能性能更好。
英文:
Unfortunately, for performance reasons (though the Go regexp parser is not particularly performant anyway), Go's regexp package does not support lookahead/lookbehind, so there is no great way to do this using regular expressions.
Regular expressions aren't a great fit for this anyway, though. It requires a very complex expression to do a very simple match. If I were implementing something similar, I would probably just split the string on spaces/punctuation and do my own matching. Easier to work with and likely better performance.
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论