英文:
How to separate arrays (type structs) in Go?
问题
我刚刚创建了这段代码来尝试使用type，稍后我会解释问题。
我的代码：
package main
import (
"fmt"
"math/rand"
"time"
)
type Games struct {
game string
creator string
}
func main() {
videogames := []Games{
{"inFamous", "Sucker Punch Games"},
{"Halo", "343 Games"},
{"JustCause", "Eidos"},
}
rand.Seed(time.Now().UTC().UnixNano())
i := rand.Intn(len(videogames))
fmt.Print(videogames[i])
}
如果我运行这段代码，结果将是：
{inFamous,Sucker Punch Games}
现在我想要做的是将数组分开，使结果变为：
游戏 = inFamous
发行商 = Sucker Punch Games
另外，我需要去掉开头和结尾的大括号。
英文:
I just created this code to experiment with type, i will explain the problems later.
My Code:
package main
import (
"fmt"
"math/rand"
"time"
)
type Games struct {
game string
creator string
}
func main() {
videogames := []Games{
{"inFamous", "Sucker Punch Games"},
{"Halo", "343 Games"},
{"JustCause", "Eidos"},
}
rand.Seed(time.Now().UTC().UnixNano())
i := rand.Intn(len(videogames))
fmt.Print(videogames[i])
}
If I run this the result will be,
{inFamous,Sucker Punch Games}
Now what i want to do is separate the arrays so that the result will be,
Game = inFamous
Publisher = Sucker Punch Games
Also i need to remove the opening and closing brackets.
答案1
得分: 3
你需要一个字符串方法来定义对象的打印方式：
func (g Games) String() string {
return fmt.Sprintf("Game = %v, Creator = %v", g.game, g.creator)
}
请查看Go之旅。
英文:
You need a stringer method to define how your object will be printed:
func (g Games) String() string {
return fmt.Sprintf("Game = %v, Creator = %v", g.game, g.creator)
}
Check out the Tour of Go
答案2
得分: 1
fmt.Print()不允许你指定格式，而是使用类型的默认格式。
相反，使用fmt.Printf()。这应该可以满足你的需求：
fmt.Printf("Game = %s\nPublisher = %s", videogames[i].game, videogames[i].creator)
英文:
fmt.Print() does not allow you to specify the format, but will use the type default format.
Instead, use fmt.Printf(). This should do what you need:
fmt.Printf("Game = %s\nPublisher = %s", videogames[i].game, videogames[i].creator)
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