在Golang中向预处理语句传递字符串

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英文:

Passing String to Prepared Statement in Golang

问题

我理解你的问题是关于更新状态并且只在状态不同的情况下返回id的问题。

你的准备语句如下所示:

var theQuery = `UPDATE process SET status=$1 WHERE status!=$1 AND id=$2 RETURNING id`

然后,你使用以下代码调用它:

err = statement.QueryRow("set", 12).Scan(&id)

然后出现了以下错误:

runtime error: invalid memory address or nil pointer dereference

当你尝试使用以下代码时:

var theQuery = `UPDATE process SET status='$1' WHERE status!='$1' AND id=$2 RETURNING id`

它可以正常运行。然后,当你再次运行它时,你期望得到no rows,但它仍然返回了id。看起来它仍然更新了行并忽略了status!='$1'部分。

谢谢。

英文:

The idea is I want to update the status and returning the id only if the status is different.

So, I have a prepared statement like this:

var theQuery = `UPDATE process SET status=$1 WHERE status!=$1 AND id=$2 RETURNING id`

Then, I called it with this:

err = statement.QueryRow("set", 12).Scan(&id)

Then there is an error appear like this.

runtime error: invalid memory address or nil pointer dereference

When I tried:

var theQuery = `UPDATE process SET status='$1' WHERE status!='$1' AND id=$2 RETURNING id`

It runs. Then, when I run it again, I am expecting to get no rows, but it still returning the id. It looked like it still updating the rows and ignored the status!='$1' part.

Thank you

答案1

得分: 1

所以,我刚刚找到了解决方案。不再使用$1两次,而是准备好的语句将接收3个参数:

var theQuery = `UPDATE process SET status=$1 WHERE status!=$2 AND id=$3 RETURNING id`

然后,我这样调用准备好的语句。

status := "set"
err = statement.QueryRow(status, status, 12).Scan(&id)

我知道这可能不是解决问题的最佳方法。但对我来说有效。

英文:

So, I just find the solution. Instead of using $1 twice, the prepared statement will received 3 arguments:

var theQuery = `UPDATE process SET status=$1 WHERE status!=$2 AND id=$3 RETURNING id`

Then, I call the prepared statement like this.

status := "set"
err = statement.QueryRow(status, status, 12).Scan(&id)

I know maybe this is not the best approach to solve the problem. But it worked for me.

huangapple
  • 本文由 发表于 2017年7月5日 20:09:24
  • 转载请务必保留本文链接:https://go.coder-hub.com/44925875.html
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