英文:
Serialize int with xml node name in go
问题
我正在学习Go语言，但是在控制XML序列化方面遇到了一些问题。
我想将一个整数序列化为<number>1</number>，我尝试了以下代码：
package main
import (
"fmt"
"encoding/xml"
)
type number struct {
Number int64
}
func main() {
out, _ := xml.Marshal(number{2})
fmt.Println(string(out))
}
但是我得到的结果是<number><Number>2</Number></number>，这是因为它被包含在结构体中导致了双重包装。如果我只序列化一个整数，我得到的结果是<int>2</int>，这个命名不正确。
有没有办法告诉序列化器不要渲染根节点，或者直接将属性放入父节点中？
英文:
I'm just in the process of learning me some go, but im having trouble controlling XML serialization
I want to serialize an int to <number>1</number>, i have tried the following:
package main
import (
"fmt"
"encoding/xml"
)
type number struct {
Number int64
}
func main() {
out, _ := xml.Marshal(number{2})
fmt.Println(string(out))
}
(https://play.golang.org/p/Ac-p1q3ytZ)
but I get <number><Number>2</Number></number> which is double wrapped due to the struct its in. If I just serialize an int I get <int>2</int> which is not named correctly.
Is there a way to tell the serialize not to render the root node, or to put a property directly into the parent?
答案1
得分: 1
是的。根据xml.Marshal的文档，你可以使用标签",chardata"。
type number struct {
Number int64 `xml:",chardata"`
}
这将输出<number>2</number>，可以在https://play.golang.org/p/Aoqfs04OTx中看到。
英文:
Yes. As per the documentation for xml.Marshal, you can use the tag ",chardata".
type number struct {
Number int64 `xml:",chardata"`
}
This outputs <number>2</number>, as seen at https://play.golang.org/p/Aoqfs04OTx
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