Golang:多个结构体的编组问题:JSON格式

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英文:

Golang: Multiple structs marshall issue: json format

问题

对于以下代码,我得到了错误:

type A struct{
	B_j []B `json:"A"` 
}
type B struct
{
	X string
	Y string
}

func main() {
	xmlFile, _ := os.Open("test.xml")

	b, _ := ioutil.ReadAll(xmlFile)

	var t root
	err2 := xml.Unmarshal(b, &rpc)
	if err2 != nil {
		fmt.Printf("error: %v", err2)
		return
	}

	for _, name := range t.name{
		t := A{B_j : []B{X : name.text, Y: name.type }} // line:#25
		
		s, _ := json.MarshalIndent(t,""," ")
        
        os.Stdout.Write(s)
	}
}

# command-line-arguments
./int2.go:25: undefined: X
./int2.go:25: cannot use name.Text (type string) as type B in array or slice literal
./int2.go:25: undefined: Y
./int2.go:25: cannot use name.type (type string) as type B in array or slice literal

在我的输出中,我试图实现以下效果:

{A: {{X:1 ,Y: 2}, {X:2 ,Y: 2}, {X: 2,Y: 2}}}

结构体调用另一个结构体以获得上述模式。

英文:

For the following code, I get the error:

type A struct{
	B_j []B `json:"A"` 
}
type B struct
{
	X string
	Y string

}

func main() {
	xmlFile, _ := os.Open("test.xml")

	b, _ := ioutil.ReadAll(xmlFile)

	var t root
	err2 := xml.Unmarshal(b, &rpc)
	if err2 != nil {
		fmt.Printf("error: %v", err2)
		return
	}

	for _, name := range t.name{
  		t := A{B_j : []B{X : name.text, Y: name.type }} // line:#25
		
		s, _ := json.MarshalIndent(t,"", " ")
        
    os.Stdout.Write(s)
		}
}

# command-line-arguments
./int2.go:25: undefined: X
./int2.go:25: cannot use name.Text (type string) as type B in array or slice literal
./int2.go:25: undefined: Y
./int2.go:25: cannot use name.type (type string) as type B in array or slice literal

In my output, I am trying to achieve something like this:

{A: {{X:1 ,Y: 2}, {X:2 ,Y: 2}, {X: 2,Y: 2}}}

Struct calling another struct to get the pattern above.

答案1

得分: 1

看起来你在这一行有问题:

t := A{B_j: []B{X: name.text, Y: name.type }}

你没有正确创建一个切片。尝试以下方式:

t := A{B_j: []B{{X: name.text, Y: name.type}}}

我们可以用更好的方式来做:

var bj []B
for _, name := range t.name{
  bj = append(bj, B{X: name.text,Y: name.type})
}

t := A{B_j: bj}
s, _ := json.MarshalIndent(t,""," ")
os.Stdout.Write(s)

带有静态值的示例程序:https://play.golang.org/p/a2ZDV8lgWP

注意:type 是语言关键字,请不要将其用作变量名。

英文:

It seems you have problem at this line-

t := A{B_j: []B{X: name.text, Y: name.type }}

You're not creating a slice properly. Try following-

t := A{B_j: []B{{X: name.text, Y: name.type}}}

Let's do it better way-

var bj []B
for _, name := range t.name{
  bj = append(bj, B{X: name.text,Y: name.type})
}

t := A{B_j: bj}
s, _ := json.MarshalIndent(t,"", " ")      
os.Stdout.Write(s)

Sample program with static values https://play.golang.org/p/a2ZDV8lgWP

Note: type is language keyword, do not use it as variable name.

huangapple
  • 本文由 发表于 2017年6月17日 03:09:10
  • 转载请务必保留本文链接:https://go.coder-hub.com/44596373.html
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