隐藏 Golang 消息

huangapple go评论94阅读模式
英文:

Hide golang messages

问题

是否可以隐藏golang的消息?我给你展示一个例子:

package main

import (
	"flag"
	"fmt"
	"os"
)

var signal = flag.String("z", "", "")

func main() {

	flag.Usage = func() {
		fmt.Printf("Usage: kata -z <command>\n\n")
		fmt.Printf("    test\tTesting\n")
		fmt.Printf("    version\tVersion\n")
		fmt.Println("")
	}

	flag.Parse()
	if len(os.Args) != 3 {
		flag.Usage()
		os.Exit(1)
	}

	switch *signal {
	case "test":
		fmt.Println("testing...")
	case "version":
		fmt.Println("0.0.1")
	default:
		fmt.Println("incorrect...")
	}
}

这个应用程序向用户显示以下信息:
https://play.golang.org/p/oYwADdmlAJ

但是,如果我在命令行中输入kata -flag,系统会返回:flag needs an argument: 或者 flag provided but not defined:,以及之前展示给你的信息。

我想知道是否可以隐藏golang的消息?

附注:如果你不理解我的问题,我可以重新表述。

英文:

Is it possible to hide the golang messages? I show you an example:

package main

import (
	&quot;flag&quot;
	&quot;fmt&quot;
	&quot;os&quot;
)

var signal = flag.String(&quot;z&quot;, &quot;&quot;, &quot;&quot;)

func main() {

	flag.Usage = func() {
		fmt.Printf(&quot;Usage: kata -z &lt;command&gt;\n\n&quot;)
		fmt.Printf(&quot;    test\tTesting\n&quot;)
		fmt.Printf(&quot;    version\tVersion\n&quot;)
		fmt.Println(&quot;&quot;)
	}

	flag.Parse()
	if len(os.Args) != 3 {
		flag.Usage()
		os.Exit(1)
	}

	switch *signal {
	case &quot;test&quot;:
		fmt.Println(&quot;testing...&quot;)
	case &quot;version&quot;:
		fmt.Println(&quot;0.0.1&quot;)
	default:
		fmt.Println(&quot;incorrect...&quot;)
	}
}

This app show to user the next information:
https://play.golang.org/p/oYwADdmlAJ

But if I write in the command-line kata -flag, the system returns: flag needs an argument: or flag provided but not defined: and the information that I show you before.

I would like to know if it's possible to hide the golang messages?

P.S.: If you don't understand my question, I can rephrase.

答案1

得分: 4

flag中使用全局函数实际上是通过一个名为flag.CommandLine的全局flag.FlagSet进行的。在内部,它将错误输出到一个默认为stderr的输出流。你可以通过将其显式设置为ioutil.Discard来抑制这些消息:

flag.CommandLine.SetOutput(ioutil.Discard)
flag.Parse()

这将丢弃flag.Parse()内部输出的所有消息。你也可以通过传递适当的io.Writer将其记录到其他任何位置。

英文:

Using the global functions in flag actually passes through to a global flag.FlagSet called flag.CommandLine. Internally, this prints errors to an output, which is stderr by default. You can suppress the messages by setting this explicitly to, for example, ioutil.Discard:

flag.CommandLine.SetOutput(ioutil.Discard)
flag.Parse()

This will discard all messages output internally by flag.Parse(). You could also log it to anywhere else you choose by passing in an appropriate io.Writer.

答案2

得分: 0

我找到了一个解决方案:

之前的代码:

flag.Parse()
if len(os.Args) != 3 {
    flag.Usage()
    os.Exit(1)
}

现在的代码:

if len(os.Args) != 3 || os.Args[1] != "-z" {
    flag.Usage()
    os.Exit(1)
} else {
    flag.Parse()
}
英文:

I have found a solution:

Before:

flag.Parse()
if len(os.Args) != 3 {
    flag.Usage()
    os.Exit(1)
}

Now:

if len(os.Args) != 3 || os.Args[1] != &quot;-z&quot; {
	flag.Usage()
	os.Exit(1)
} else {
	flag.Parse()
}

huangapple
  • 本文由 发表于 2017年6月9日 23:19:16
  • 转载请务必保留本文链接:https://go.coder-hub.com/44461407.html
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