英文:
Cannot unmarshal object into Go value of type []uint8
问题
我对Go相当新手。我有以下代码：
package main
import (
"encoding/json"
"fmt"
)
func main() {
byt := []byte(`{"num":6.13,"strs":["a","b"]}`)
dat := []byte(`{"num":7.13,"strs":["c","d"]}`)
if err := json.Unmarshal(byt, &dat); err != nil {
panic(err)
}
fmt.Println(dat)
}
出现了以下错误：
无法将对象解组为类型为 []uint8 的Go值。
请问我该如何修复这个问题？
英文:
I am fairly new to Go. I have the following code:
package main
import (
"encoding/json"
"fmt"
)
func main() {
byt := []byte(`{"num":6.13,"strs":["a","b"]}`)
dat := []byte(`{"num":7.13,"strs":["c","d"]}`)
if err := json.Unmarshal(byt, &dat); err != nil {
panic(err)
}
fmt.Println(dat)
}
Getting the error:
> cannot "unmarshal object into Go value of type []uint8".
How can I fix this please?
答案1
得分: 9
你有两个JSON输入，并且你试图将一个解组成另一个。这没有任何意义。
使用一个类型（结构体）对你的JSON输入（对象）进行建模，并将其解组成该类型。例如：
type Obj struct {
Num float64 `json:"num"`
Strs []string `json:"strs"`
}
func main() {
byt := []byte(`{"num":6.13,"strs":["a","b"]}`)
var obj Obj
if err := json.Unmarshal(byt, &obj); err != nil {
panic(err)
}
fmt.Println(obj)
}
输出结果（在Go Playground上尝试）：
{6.13 [a b]}
英文:
You have 2 JSON inputs, and you're trying to unmarshal one into the other. That doesn't make any sense.
Model your JSON input (the object) with a type (struct), and unmarshal into that. For example:
type Obj struct {
Num float64 `json:"num"`
Strs []string `json:"strs"`
}
func main() {
byt := []byte(`{"num":6.13,"strs":["a","b"]}`)
var obj Obj
if err := json.Unmarshal(byt, &obj); err != nil {
panic(err)
}
fmt.Println(obj)
}
Output (try it on the Go Playground):
{6.13 [a b]}
答案2
得分: 2
我认为你的意思是这样的：
package main
import (
"encoding/json"
"fmt"
)
func main() {
var dat interface{}
byt := []byte(`{"num":6.13,"strs":["a","b"]}`)
if err := json.Unmarshal(byt, &dat); err != nil {
panic(err)
}
fmt.Println(dat)
}
你尝试的操作没有意义，因为你试图将一个 JSON 对象解组成另一个 JSON 对象。
英文:
I think you meant to do something like this:
package main
import (
"encoding/json"
"fmt"
)
func main() {
var dat interface{}
byt := []byte(`{"num":6.13,"strs":["a","b"]}`)
if err := json.Unmarshal(byt, &dat); err != nil {
panic(err)
}
fmt.Println(dat)
}
What you were trying to do makes no sense, since you're trying to unmarshal two JSON objects one into another.
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