英文:
How can you upload files as a []byte in go?
问题
我想使用golang进行POST请求并上传图片，但我不想传递文件路径，只想传递[]byte类型的数据。
以下是我找到的一篇文章，但不符合我的需求，因为它使用了os.Open函数：
https://stackoverflow.com/questions/20205796/golang-post-data-using-the-content-type-multipart-form-data
func Upload(url, file string) (err error) {
// 准备一个表单，将要提交到指定的URL。
var b bytes.Buffer
w := multipart.NewWriter(&b)
// 添加图片文件
f, err := os.Open(file)
if err != nil {
return
}
defer f.Close()
fw, err := w.CreateFormFile("image", file)
if err != nil {
return
}
if _, err = io.Copy(fw, f); err != nil {
return
}
// 添加其他字段
if fw, err = w.CreateFormField("key"); err != nil {
return
}
if _, err = fw.Write([]byte("KEY")); err != nil {
return
}
// 不要忘记关闭multipart writer。
// 如果不关闭，请求将缺少终止边界。
w.Close()
// 现在你有了一个表单，可以将其提交给处理程序。
req, err := http.NewRequest("POST", url, &b)
if err != nil {
return
}
// 不要忘记设置Content-Type，它将包含边界信息。
req.Header.Set("Content-Type", w.FormDataContentType())
// 提交请求
client := &http.Client{}
res, err := client.Do(req)
if err != nil {
return
}
// 检查响应
if res.StatusCode != http.StatusOK {
err = fmt.Errorf("bad status: %s", res.Status)
}
return
}
希望这可以帮到你！
英文:
I would like to use golang post request, upload pictures, but I do not want to pass filepath, just want to pass [] byte
The following article are not what I need because they are used os.Open
https://stackoverflow.com/questions/20205796/golang-post-data-using-the-content-type-multipart-form-data
func Upload(url, file string) (err error) {
// Prepare a form that you will submit to that URL.
var b bytes.Buffer
w := multipart.NewWriter(&b)
// Add your image file
f, err := os.Open(file)
if err != nil {
return
}
defer f.Close()
fw, err := w.CreateFormFile("image", file)
if err != nil {
return
}
if _, err = io.Copy(fw, f); err != nil {
return
}
// Add the other fields
if fw, err = w.CreateFormField("key"); err != nil {
return
}
if _, err = fw.Write([]byte("KEY")); err != nil {
return
}
// Don't forget to close the multipart writer.
// If you don't close it, your request will be missing the terminating boundary.
w.Close()
// Now that you have a form, you can submit it to your handler.
req, err := http.NewRequest("POST", url, &b)
if err != nil {
return
}
// Don't forget to set the content type, this will contain the boundary.
req.Header.Set("Content-Type", w.FormDataContentType())
// Submit the request
client := &http.Client{}
res, err := client.Do(req)
if err != nil {
return
}
// Check the response
if res.StatusCode != http.StatusOK {
err = fmt.Errorf("bad status: %s", res.Status)
}
return
}
答案1
得分: 1
由于您使用了以下代码：
if _, err = io.Copy(fw, f); err != nil {
return
}
您可以对代码进行如下修改：
- 添加新的导入：
"bytes" - 将方法签名修改为
func Upload(url string, file []byte) (err error) - 使用
io.Copy(fw, bytes.NewReader(f))
英文:
Since you use
if _, err = io.Copy(fw, f); err != nil {
return
}
You may as well edit your code to:
- Add new import:
"bytes" - Change the method signature to
func Upload(url string, file []byte) (err error) - Use
io.Copy(fw, bytes.NewReader(f))
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