如何使这个斐波那契数列生成器更加优雅？

huangapple
go评论108阅读模式
英文:

How do I make this Fibonacci sequence generator more elegant?

问题

以下是你提供的代码的中文翻译：

  1. package main
  3. import "fmt"
  5. func fib_seq() func() int {
  6. 	n0, n1 := 0, 1
  8. 	return func() int {
  9. 		result := n0
  10. 		n0, n1 = n1, n0 + n1
  11. 		return result
  12. 	}
  13. }
  15. func main() {
  16. 	f := fib_seq()
  17. 	for i := 0; i < 10; i++ {
  18. 		fmt.Println(f())
  19. 	}
  20. }

这是一个生成斐波那契数列的程序。result 的定义是不需要的（但是必要的）。

我想知道在 return 之后是否有一种方法可以执行 x, y = y, x + y？

英文: 
  1. package main
  3. import &quot;fmt&quot;
  5. func fib_seq() func() int {
  6. 	n0, n1 := 0, 1
  8. 	return func() int {
  9. 		result := n0
  10. 		n0, n1 = n1, n0 + n1
  11. 		return result
  12. 	}
  13. }
  15. func main() {
  16. 	f := fib_seq()
  17. 	for i := 0; i &lt; 10; i++ {
  18. 		fmt.Println(f())
  19. 	}
  20. }

This is my Fibonacci sequence generator. The definition of result is unwanted (but necessary).

I wonder is there a way to execute x, y = y, x + y after return?

答案1

得分: 3

你可能想要看一下defer：

  1. func fib_seq() func() int {
  2.     n0, n1 := 0, 1
  4.     return func() int {
  5.         defer func() {
  6.             n0, n1 = n1, n0 + n1
  7.         }()
  9.         return n0
  10.     }
  11. }
英文:

You may want to take a look at defer:

  1. func fib_seq() func() int {
  2.     n0, n1 := 0, 1
  4.     return func() int {
  5.         defer func() {
  6.             n0, n1 = n1, n0 + n1
  7.         }()
  9.         return n0
  10.     }
  11. }

答案2

得分: 2

命名返回。但是你已经有了足够可读的内容。

  1. func fib_seq() func() int {
  2.     n0, n1 := 0, 1
  4.     return func() (r int) {
  5.         r, n0, n1 = n0, n1, n0 + n1
  6.         return
  7.     }
  8. }
英文:

Named return. But what you have is already readable enough.

  1. func fib_seq() func() int {
  2.     n0, n1 := 0, 1
  4.     return func() (r int) {
  5.         r, n0, n1 = n0, n1, n0 + n1
  6.         return
  7.     }
  8. }

答案3

得分: 0

个人而言，我更喜欢以下的代码（为了可读性）：

  1. type fib struct{ n0, n1 int }
  3. func (f *fib) next() int {
  4.     defer func() { 
  5.         f.n0, f.n1 = f.n1, f.n0+f.n1 
  6.     }()
  7.     return f.n0
  8. }
  10. func main() {
  11.     fib := &fib{0, 1}
  12.     for i := 0; i < 10; i++ {
  13.         fmt.Println(fib.next())
  14.     }
  15. }

请注意，我只提供了代码的翻译部分，不包括其他内容。

英文:

Personally, I'd prefer the following (for readability):

  1. type fib struct{ n0, n1 int }
  3. func (f *fib) next() int {
  4. 	defer func() { 
  5.         f.n0, f.n1 = f.n1, f.n0+f.n1 
  6.     }()
  7. 	return f.n0
  8. }
  10. func main() {
  11. 	fib := &amp;fib{0, 1}
  12. 	for i := 0; i &lt; 10; i++ {
  13. 		fmt.Println(fib.next())
  14. 	}
  15. }

答案4

得分: 0

“优雅”对不同的人来说有不同的含义。对一些人来说，它可能意味着“简洁”，对其他人来说可能意味着“简单”或“易读”。

这是我的理解：

  1. public class Fibonacci {
  3. 	private static int x;
  4. 	private static int y;
  5. 	private static int z;
  7. 	public static void main(String[] args) {
  8. 		x = 0;
  9. 		y = 1;
  10. 		z = 0;
  12. 		System.out.println(x);
  13. 		System.out.println(y);
  14. 		while (z < 100) {
  15. 			z = x + y;
  16. 			System.out.println(z);
  17. 			x = y;
  18. 			y = z;
  19. 		}
  20. 		
  21. 	}
  22. }

如你所见，我更注重代码的可读性而非复杂性 如何使这个斐波那契数列生成器更加优雅？

英文:

"Elegant" means different things to different people. To some it may mean "conciseness," and to others it may mean "simplicity," or "readability."

Here is my take on it:

  1. public class Fibonacci {
  3. 	private static int x;
  4. 	private static int y;
  5. 	private static int z;
  7. 	public static void main(String[] args) {
  8. 		x = 0;
  9. 		y = 1;
  10. 		z = 0;
  12. 		System.out.println(x);
  13. 		System.out.println(y);
  14. 		while (z &lt; 100) {
  15. 			z = x + y;
  16. 			System.out.println(z);
  17. 			x = y;
  18. 			y = z;
  19. 		}
  20. 		
  21. 	}
  22. }

As you can see, I favor readability over sophistication 如何使这个斐波那契数列生成器更加优雅？

huangapple
  • 本文由 发表于 2017年5月29日 20:42:38
  • 转载请务必保留本文链接：https://go.coder-hub.com/44242803.html
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