英文:
Why is GorillaMux not allowing me to pass in a URL as a parameter?
问题
我正在构建一个URL缩短器API，并尝试使用GorillaMux将URL传递给一个函数。路由处理程序如下所示：
router.HandleFunc("/new/{url}", createURL)
唯一的问题是，如果我传入：https://www.google.com（即localhost:8080/new/https://www.google.com），它会响应404页面未找到，并且URL会更改为https:/www.google.com。
我尝试在{url}部分中添加一个正则表达式模式，如下所示：{url:[a-zA-Z0-9/]+}，但似乎没有起作用，并且似乎有点过度，因为我在其他地方已经检查了URL是否正确。
英文:
I'm building a URL shortener API and I'm trying to pass a URL into a function using GorillaMux. The route handler is like so:
router.HandleFunc("/new/{url}", createURL)
The only thing is, if I pass in: https://www.google.com (as in localhost:8080/new/https://www.google.com) then it responds with 404 page not found and the URL is changed to https:/www.google.com.
I've tried adding a regexp pattern in with the {url} bit like so: {url:[a-zA-Z0-9/]+} but that didn't seem to work and seems a bit overkill since I'm checking the url is correct elsewhere.
答案1
得分: 3
你需要对其进行编码，以免参数中的斜杠被误认为是URL的一部分：
localhost:8080/new/https%3A%2F%2Fwww.google.com
英文:
You need to encode it so that the slash in the parameter was not confused as a part of the url:
localhost:8080/new/https%3A%2F%2Fwww.google.com
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