英文:
Golang :How to parse/unmarshal/decode a json array API response?
问题
我正在尝试解析来自维基百科API的响应,该API位于https://wikimedia.org/api/rest_v1/metrics/pageviews/per-article/en.wikipedia.org/all-access/all-agents/Smithsonian_Institution/daily/20160101/20170101
,并将其解析为一个结构体数组,然后我将打印出查看次数。
然而,我尝试实现此功能的代码在构建和运行时没有在终端中返回任何内容。
我无法成功的代码如下:
type Post struct {
Project string `json:"project"`
Article string `json:"article"`
Granularity string `json:"granularity"`
Timestamp string `json:"timestamp"`
Access string `json:"access"`
Agent string `json:"agent"`
Views int `json:"views"`
}
func main() {
//The name of the wikipedia post
postName := "Smithsonian_Institution"
//The frequency of
period := "daily"
//When to start the selection
startDate := "20160101"
//When to end the selection
endDate := "20170101"
url := fmt.Sprintf("https://wikimedia.org/api/rest_v1/metrics/pageviews/per-article/en.wikipedia.org/all-access/all-agents/%s/%s/%s/%s", postName, period, startDate, endDate)
//Get from URL
req, err := http.Get(url)
if err != nil {
return
}
defer req.Body.Close()
var posts []Post
body, err := ioutil.ReadAll(req.Body)
if err != nil {
panic(err.Error())
}
json.Unmarshal(body, &posts)
// Loop over structs and display the respective views.
for p := range posts {
fmt.Printf("Views = %v", posts[p].Views)
fmt.Println()
}
}
请问,从上述API接收JSON响应并将其解析为结构体数组的最佳方法是什么,然后可以将其插入到数据存储中或相应地打印出来。
谢谢。
英文:
I am trying to parse the response from Wikipedia's API located at https://wikimedia.org/api/rest_v1/metrics/pageviews/per-article/en.wikipedia.org/all-access/all-agents/Smithsonian_Institution/daily/20160101/20170101
into an array of structs of which I will proceed to print out the view count
However, the code that I have tried to implement in order to achieve this returns nothing in the terminal when I build and run it?
The code I am failing to succeed with is as follows.
type Post struct {
Project string `json:"project"`
Article string `json:"article"`
Granularity string `json:"granularity"`
Timestamp string `json:"timestamp"`
Access string `json:"access"`
Agent string `json:"agent"`
Views int `json:"views"`
}
func main(){
//The name of the wikipedia post
postName := "Smithsonian_Institution"
//The frequency of
period := "daily"
//When to start the selection
startDate := "20160101"
//When to end the selection
endDate := "20170101"
url := fmt.Sprintf("https://wikimedia.org/api/rest_v1/metrics/pageviews/per-article/en.wikipedia.org/all-access/all-agents/%s/%s/%s/%s", postName, period, startDate, endDate)
//Get from URL
req, err := http.Get(url)
if err != nil{
return
}
defer req.Body.Close()
var posts []Post
body, err := ioutil.ReadAll(req.Body)
if err != nil {
panic(err.Error())
}
json.Unmarshal(body, &posts)
// Loop over structs and display the respective views.
for p := range posts {
fmt.Printf("Views = %v", posts.Views)
fmt.Println()
}
}
What is the optimal method of receiving a json response from a API such as the one mentioned above and thereafter parsing that array into an array of structs, which can then be inserted into a datastore or printed out accordingly.
Thanks
答案1
得分: 19
结构声明可以嵌套在彼此内部。
以下结构应该可以从该JSON转换而来:
type resp struct {
Items []struct {
Project string `json:"project"`
Article string `json:"article"`
Granularity string `json:"granularity"`
Timestamp string `json:"timestamp"`
Access string `json:"access"`
Agent string `json:"agent"`
Views int `json:"views"`
} `json:"items"`
}
我使用 json-to-go 生成了上述代码,这是一个在使用JSON API时非常方便的时间节省工具。
英文:
Struct declarations can be nested inside one another.
The following struct should be convertable from that json:
type resp struct {
Items []struct {
Project string `json:"project"`
Article string `json:"article"`
Granularity string `json:"granularity"`
Timestamp string `json:"timestamp"`
Access string `json:"access"`
Agent string `json:"agent"`
Views int `json:"views"`
} `json:"items"`
}
I generated that with json-to-go, which is a great time saver when working with JSON APIs.
答案2
得分: 9
你的解决方案:
data := struct {
Items []struct {
Project string `json:"project"`
Article string `json:"article"`
Granularity string `json:"granularity"`
Timestamp string `json:"timestamp"`
Access string `json:"access"`
Agent string `json:"agent"`
Views int `json:"views"`
} `json:"items"`
}{}
// 你不需要将 body 转换为 []byte,ReadAll 返回 []byte
err := json.Unmarshal(body, &data)
if err != nil { // 不要忘记处理错误
}
英文:
Your solution:
data := struct {
Items []struct {
Project string `json:"project"`
Article string `json:"article"`
Granularity string `json:"granularity"`
Timestamp string `json:"timestamp"`
Access string `json:"access"`
Agent string `json:"agent"`
Views int `json:"views"`
} `json:"items"`
}{}
// you don't need to convert body to []byte, ReadAll returns []byte
err := json.Unmarshal(body, &data)
if err != nil { // don't forget handle errors
}
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库,让每个人都能够通过互相帮助和分享经验来进步。
评论