英文:
GOLANG xml decoding
问题
在Go语言中，我正在尝试将这个XML解码为"fileRetriever"结构体。我只关心文件名：
<?xml version="1.0" encoding="ISO-8859-1"?>
<FileRetriever>
<FileList>
<File name="Name1" />
<File name="Name2" />
</FileList>
</FileRetriever>
我认为这段代码很接近，但我似乎找不到错误所在。它没有产生错误，但文件名列表的长度为零：
import (
"encoding/base64"
"encoding/xml"
"fmt"
"net/http"
"golang.org/x/net/html/charset"
)
type fileRetriever struct {
Files []file `xml:"FileRetriever>FileList>File"`
}
type file struct {
Name string `xml:"name,attr"`
}
func Main(){
retrieve()
}
func retrieve()(retriever *fileRetriever){
req := ... //设置http.NewRequest()
client := &http.Client{}
rsp, err := client.Do(req)
if err != nil {
log.Fatal(err)
}
defer rsp.Body.Close()
decoder := xml.NewDecoder(rsp.Body)
decoder.CharsetReader = charset.NewReaderLabel
retriever = &fileRetriever{}
err = decoder.Decode(&retriever)
if err != nil {
fmt.Println(err)
}
return retriever, xTidx
}
英文:
In Go, I'm trying to decode this XML into the "fileRetriever" struct. I only care about the file names:
<?xml version="1.0" encoding="ISO-8859-1" ?>
<FileRetriever>
<FileList>
<File name="Name1" />
<File name="Name2" />
</FileList>
</FileRetriever>
I think this code snippet is close, but I can't seem to see where I'm going wrong. It produces no errors, but also a zero-length list of file names:
import (
"encoding/base64"
"encoding/xml"
"fmt"
"net/http"
"golang.org/x/net/html/charset"
)
type fileRetriever struct {
Files []file `xml:"FileRetriever>FileList>File"`
}
type file struct {
Name string `xml:"name,attr"`
}
func Main(){
retrieve()
}
func retrieve()(retriever *fileRetriever){
req := ... //set up http.NewRequest()
client := &http.Client{}
rsp, err := client.Do(req)
if err != nil {
log.Fatal(err)
}
defer rsp.Body.Close()
decoder := xml.NewDecoder(rsp.Body)
decoder.CharsetReader = charset.NewReaderLabel
retriever = &fileRetriever{}
err = decoder.Decode(&retriever)
if err != nil {
fmt.Println(err)
}
return retriever, xTidx
}
答案1
得分: 4
根元素会自动解码为您传递给Decode的值，因此您不需要在Files字段标签中提及它。
所以只需将xml:"FileRetriever>FileList>File"更改为xml:"FileList>File"。
英文:
The root element is automatically decoded into the value you pass to Decode so you don't need to mention it in the Files field tag.
So just change xml:"FileRetriever>FileList>File" to xml:"FileList>File".
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