英文:
Setting a value in structure fails
问题
我在结构体中设置了值，但是没有生效。方法是按顺序调用的，而不是并行调用的。这是使用golang编写的代码，我忘了提醒你了。
如果我将代码更改为在"start"方法中设置值（而不是"init"方法），它可以正常工作；但是在"init"方法中设置值会失败。对我来说看起来非常奇怪。
以下是代码：
package mainimport ("log""net/http""time")type tServer struct {ipAddress stringport stringserver http.Server}var server tServerfunc main() {server.ipAddress = "0.0.0.0"server.port = "12345"server.init()server.start()time.Sleep(time.Second * 5)}func (srv tServer) init() {srv.server.Addr = srv.ipAddress + ":" + srv.portlog.Println("srv.server.Addr=", srv.server.Addr) ////////////////////}func (srv tServer) start() {log.Println("srv.server.Addr=", srv.server.Addr) ////////////////////go srv.startServerRoutine()}func (srv tServer) startServerRoutine() {log.Println("Server started at", srv.server.Addr) //err := srv.server.ListenAndServe()if err != nil {log.Println("Server Error:", err) //return}}
这是控制台输出：
2017/04/18 19:43:07 srv.server.Addr= 0.0.0.0:123452017/04/18 19:43:07 srv.server.Addr=2017/04/18 19:43:07 Server started at2017/04/18 19:43:07 Server Error: listen tcp :80: bind: permission denied
请注意，根据你的代码，我无法提供关于为什么在"init"方法中设置值失败的具体原因。但是，根据输出结果，可以看出在"start"方法中设置值是有效的，而在"init"方法中设置值则失败了。
英文:
I set the value in the structure, but it is not set. The methods are called consequently, not in parallel. How can that be? This is golang, forgot to say.
If I change the code to set value in the "start" method (instead of "init" method), it works; but setting value in "init" method fails. Looks very strange to me.
package mainimport ("log""net/http""time")type tServer struct {ipAddress stringport stringserver http.Server}var server tServerfunc main() {server.ipAddress = "0.0.0.0"server.port = "12345"server.init()server.start()time.Sleep(time.Second * 5)}func (srv tServer) init() {srv.server.Addr = srv.ipAddress + ":" + srv.portlog.Println("srv.server.Addr=", srv.server.Addr) ////////////////////}func (srv tServer) start() {log.Println("srv.server.Addr=", srv.server.Addr) ////////////////////go srv.startServerRoutine()}func (srv tServer) startServerRoutine() {log.Println("Server started at", srv.server.Addr) //err := srv.server.ListenAndServe()if err != nil {log.Println("Server Error:", err) //return}}
Here is the console:
2017/04/18 19:43:07 srv.server.Addr= 0.0.0.0:123452017/04/18 19:43:07 srv.server.Addr=2017/04/18 19:43:07 Server started at2017/04/18 19:43:07 Server Error: listen tcp :80: bind: permission denied
答案1
得分: 4
这是由于方法的原型：
func (srv tServer) init()// ^^^ 复制值
所以：
server.init() // 更新自己的 server 副本，// 副本在 init() 返回后被丢弃server.start() // 使用自己的 server 副本
你需要通过指针将 srv 传递给方法：
func (srv *tServer) init()
在这种情况下，init() 和 start() 调用将在同一个 tServer 结构的副本上工作，并共享其字段中的值。
英文:
This is due to prototype of methods:
func (srv tServer) init()// ^^^ copies values
so:
server.init() // updates its own copy of server,// copy gets disposed after init() returnsserver.start() // uses its own copy of server
You need to pass srv by pointer to methods:
func (srv *tServer) init()
in that case both init() and start() calls will work on the same copy of tServer structure and will share values in its fields.
答案2
得分: 1
如果你查看http.Server的文档，你会发现可以使用空值，表示":http"：
type Server struct {Addr string // TCP address to listen on, ":http" if empty}
你在init()函数中直接设置了srv.server.Addr，但这不是正确使用http.Server类型的方式。
也许你的意思是这样做：
func (srv tServer) startServerRoutine() {log.Println("Server started at", srv.ipAddress + ":" + srv.port)err := srv.server.ListenAndServe(srv.ipAddress + ":" + srv.port)if err != nil {log.Println("Server Error:", err)return}}
英文:
If you look at the docs for http.Server you will see that a blank value is possible, and means ":http":
type Server struct {Addr string // TCP address to listen on, ":http" if empty
You set srv.server.Addr directly in init(), but this is not the proper way to use the http.Server type.
Perhaps you meant to do this:
func (srv tServer) startServerRoutine() {log.Println("Server started at", srv.ipAddress + ":" + srv.port) //err := srv.server.ListenAndServe(srv.ipAddress + ":" + srv.port)if err != nil {log.Println("Server Error:", err) //return}}
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